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mart [117]
3 years ago
9

Which equation represents the line that passes through the point (1,5) with a slope of-2

Mathematics
1 answer:
svlad2 [7]3 years ago
3 0

Answer:

The equation of the line would be y = -2x + 7

Step-by-step explanation:

In order to solve this, use the point and the slope in point-slope form. Then solve for y.

y - y1 = m(x - x1)

y - 5 = -2(x - 1)

y - 5 = -2x + 2

y = -2x + 7

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5/12-1/9 can you help me?
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Answer: 11/6

Step-by-step explanation:

5/12 - 1/9=?

\frac{5*3}{12*3}-\frac{1*4}{9*4}\\\\\frac{15}{36}-\frac{4}{36}=  \\\\15-4=11\\Answer: \frac{11}{36}

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How do I solve this question, In an arithmetic sequence, u1 = 2 and u3 =8, a) find d
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Is 22 ounces equal to 6 pound
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Suppose x=c1e−t+c2e3tx=c1e−t+c2e3t. Verify that x=c1e−t+c2e3tx=c1e−t+c2e3t is a solution to x′′−2x′−3x=0x′′−2x′−3x=0 by substitu
Harrizon [31]

The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

We differentiate

x = c1e^(-t) + c2e^(3t)

twice in succession, and substitute the values of x, x', and x'' into the differential equation

x''- 2x' - 3x = 0

and see if it is satisfied.

Let us do that.

x = c1e^(-t) + c2e^(3t)

x' = -c1e^(-t) + 3c2e^(3t)

x'' = c1e^(-t) + 9c2e^(3t)

Now,

x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]

= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)

= 0

Therefore, the differential equation is satisfied, and hence, x is a solution.

4 0
2 years ago
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