Answer:
Present Time
Let X= Eric's age (4/5)X= Seth's age
Question: What are their ages now?________________________________________________________________________
Past (21 years ago)
X-21 =Eric's age (4/5)X-21=Seth's age
2*[4/5(X-21]=Eric's age
Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution
_______________________________________________________________________
X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.
X-21+42=(8/5) X
X+21 = (8/5)X Subtract "X" from both sides.
21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3
21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.
Then find 4/5 (X)= Seth's age
(i) Pairs of <em>neighboring</em> angles are <em>supplementary</em> and <em>opposite</em> angles have the <em>same</em> measure.
(ii) The two angles formed by a line coming out of another line are <em>supplementary</em>.
<h3>
How to analyze pairs of angles</h3>
(i) When two <em>straight</em> lines pass through each other, then <em>two</em> pairs of <em>opposite</em> angles are constructed. A pair with angles of
and another pair with angles of
, each pair of angles with <em>different </em>measures are <em>supplementary</em>.
(ii) When a <em>straight</em> line comes out of another <em>straight</em> line, from a point distinct to any endpoint of the former, then we construct two <em>supplementary</em> angles. The <em>largest</em> angle has a value of
, whereas the <em>smaller</em> one has a value of
. 
To learn more on angles, we kindly invite to check this verified question: brainly.com/question/15767203
Add 3 on both sides
x = 13
I hope this helps you!
Answer:
20 percent decrease
Step-by-step explanation:
0.15 cents is 10 percent of 1.50, and that multiplied by 2 is 0.30 cents. 0.30 cents is equal to 20 percent, and the difference between 1.50 and 1.20 is 30 cents.
Answer:
Point O is the center of the circle.
<u>Part (a)</u>
is a chord.
is a segment of the radius and is perpendicular to 
If a radius is perpendicular to a chord, it bisects the chord (divides the chord into two equal parts).
Therefore, 
<u>Part (b)</u>
If
was extended past point E to touch the circumference it would be a chord.
As
is perpendicular to
, it would bisect the chord, but as
is only a portion of a chord,
<u>does not</u> bisect
.
Therefore, there is no length equal to
.