Log_(16)(x^2 - 3x + 12) = 1
x^2 - 3x +12 = 16
x^2 - 3x - 4 = 0
x = [3 ± √(3^2 - 4(1)(-4))]/[2(1)] = [3 ± 5]/2 = 4, -1
Answer:
D. Yes, because it passes the vertical line test
Answer:
10 cm³
Step-by-step explanation:
I could have used Area = height×length×width, but I counted instead :)
When I counted, I got 30/3 cm³ which is 10 cm³
Answer:
14
Step-by-step explanation: