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3 years ago

Ayo so like i'm doing logarithms and i need help how do you solve 3(5)^x=192 for the variable thanks

Mathematics

2 answers:

Leviafan [203]3 years ago

6 0

Answer:

Exact Form:

x = ln ( 64 )/ ln ( 5 )

Decimal Form:

x = 2.58405934 …

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

otez555 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Start by dividing both sides by 3

5^x = 192/3

5^x = 64

Now take the log of both sides

log(5^x) = log(64)

Bring down the power

x log(5) = log(64)

Find the logs

x * 0.69897 = 1.8062

Divide

x = 1.8062 / 0.69897

x = 2.5841

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zavuch27 [327]

Answer:

x = (y - b)/m

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First subtract b from both sides:

y = mx + b

y (-b) = mx + b (-b)

y - b = mx

Next, divide m from both sides:

(y - b)/m = (mx)/m

x = (y - b)/m

x = (y - b)/m is your answer.

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3 years ago

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Step-by-step explanation:

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3 years ago

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Westkost [7]

Answer:

1.4

Step-by-step explanation:

start by subtracting 2.6 and 4 you'll get -1.4 dont mind the negative because it doesn't matter, and now you add 1.4 to each number and that's how you get the next number. like 1.4+5.4=6.8 and 1.4+6.8=8.2, and so on.

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3 years ago

Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten

Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

$Q(t) = Q(0)e^{-rt}$

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that $Q(12) = 0.5Q(0)$

$Q(t) = Q(0)e^{-rt}$

$0.5Q(0) = Q(0)e^{-12r}$

$e^{-12r} = 0.5$

$\ln{e^{-12r}} = \ln{0.5}$

$-12r = \ln{0.5}$

$12r = -\ln{0.5}$

$r = -\frac{\ln{0.5}}{12}$

$r = 0.05776$

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

$Q(t) = Q(0)e^{-rt}$

$50 = 200e^{-0.05776t}$

$e^{-0.05776t} = 0.25$

$\ln{e^{-0.05776t}} = \ln{0.25}$

$-0.05776t = \ln{0.25}$

$0.05776t = -\ln{0.25}$

$t = -\frac{\ln{0.25}}{0.05776}$

$t = 24$

It would take 24 minutes for the element to decay to 50 grams

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3 years ago

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Answer:

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4 years ago