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melamori03 [73]
2 years ago
8

answer this if you want 70 pts who ever answers first I will brainliest and give 5 stars with a thank you and you will earn 70 p

ts you may go NOW

Mathematics
1 answer:
vivado [14]2 years ago
3 0
Just use a calculator, the answer is 442
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Suppose you have 8 dice in a bag. You draw a single die and roll it. Three dice are standard fair dice, numbered 1-6 Two dice ar
Viktor [21]

Answer:

The probability of drawing a 4 is \frac{47}{240}

Step-by-step explanation:

We will assume that each of the dices is equally likely to be drawn. So, let us consider this three events: A is the event that we draw a traditional die, B is the event that we draw a die that has two 4's on it and C is that we draw a ten sided die.

Since they are all mutually exclusive events, we have that P(A) + P(B) + P(C)=1. We will find this probability by simply counting the number of ways in which we get the specific event and divided by the total number of outcomes.

Note that since we have 8 dice, and 3 dice are fair standard dice, P(A) = 3/8.

On the same fashion, we get that P(B) = 2/8, P(C) = 3/8.

No, we will calculate the probability of getting a 4 to each type of die. Let D be the event that we get a 4. So, we will calculate the conditionals probabilities P(D|A), P(D|B), P(D|C). Recall that P(D|A) is the probability of getting a 4, given that we draw a standard fair die.

So, suppose we get a standard die. Since it is fair and standard, we have that  the probability of getting a four is 1/6. Thus P(D|A) = 1/6.

If we get a die that has two 4's, we have double the chance of getting a 4, so the probability is 2/6. Then P(D|B) = 2/6.

Now, consider the case we get a 10-sided die. In here, we will assume that all odd numbers are equally likely between them and that even numbers are equally likely between them. When we throw the die, we get a number between 1 and 10. Since all possible outcomes of throwing the die once are mutually exclusive, we must have that P(1)+P(2)+...+P(10)= 1. Let c be the probability assigned to an odd number and 2c be the probability assigned to an even number. Then we have that

c+ 2c+c+2c+c+2c+c+2c+c+2c = 5c+5*(2c) = 15c = 1

which implies that c= 1/15. Then, in this case the probability of getting a 4 is 2c, i.e 2/15. Then P(D|C) = 2/15.

We will use the following theorem (total probability theorem). Given a partition of the sample space A_1, \dots , A_n (partition means mutually exclusive events) and an event B, then

P(B) = \sum_{i=1}^{n} P(A_i)P(B|A_i)

In our case, we are asked to calculate P(D). Then, by this theorem

P(D) = P(A)\cdot P(D|A)+P(B) P(D|B) + P(C) P(D|C) = \frac{3}{8}\cdot \frac{1}{6}+\frac{2}{8}\cdot \frac{2}{6}+\frac{3}{8}\cdot \frac{2}{15}= \frac{47}{240}

6 0
3 years ago
I give out brainlist. write and solve the proportion in the complele statement.
Thepotemich [5.8K]

Answer:

42 in=106.68cm

12.6kg=27.77lb

Step-by-step explanation:

pls give brainliest! im tryna get to vituoso

4 0
2 years ago
Read 2 more answers
Any one can solve this ​
vladimir1956 [14]

Answer:

The height of water in the container is 5 cm

Step-by-step explanation:

Here, we want to calculate the height of the water in the container

Mathematically, the volume is :

50 * 30 * h = 1500h cm^3

Also, 7.5 L = 7500 cm^3 = 7.5 L

Let the height be h

1500h = 7500

h = 7500/1500

h = 5 cm

4 0
3 years ago
Point C divides segment AB so that AC:AB is 3:8. Which statement is NOT true?<br> HELP!
natima [27]

Given:

It is given that

C divides AB so that, AC:AB = 3:8

To find the wrong option among the given options.

Let us take,

AB = 8x unit

AC = 3x unit

So,

CB = 8x-3x

CB = 5x unit

So, we can conclude that,

AC: CB: AB = 3:5:8

Hence,

The wrong option is C i.e, Point C is \frac{3}{5} of way from point A to point B.

6 0
3 years ago
The class president collected data on 150 randomly selected 17-year-olds at his school. He surveyed students on if they had a jo
telo118 [61]

Answer:

Step-by-step explanation:

Part A can be seen in the attached picture below. Since there are 76 students that have both a license and a job we need to subtract 76 from each to get the amount that only have either a license or a job as seen in the table. Also we can see from the table that it sums up to 145 students, meaning that 5 students do not have neither a job or a license.

Part B, to calculate this we need to divide the amount of students that ONLY have a job by the total amount of students that have a job (since the rest of those students also have a license) Therefore:

17 / 93 = 0.1828

Now we can multiply this result by 100 to get the percentage.

0.1828 * 100 = 18.28%

8 0
3 years ago
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