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Gala2k [10]
2 years ago
9

Montrey recently paid off his simple interest loan. If he borrowed $6,500 for 5 years at 7%, what was the total amount he had to

pay back?
Mathematics
1 answer:
erica [24]2 years ago
6 0

9514 1404 393

Answer:

  $8,775

Step-by-step explanation:

The amount due is given by the formula ...

  A = P(1 +rt)

where P is the principal amount, r is the annual rate, and t is the number of years.

  A = $6,500(1 +0.07×5) = $6,500(1.35) = $8,775

Montrey had to pay back $8,775.

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3 years ago
A 6-pack of light bulbs costs $7.38. What is the unit price?
Alika [10]

Answer:

ever beer cost 1.38 so that is it

7 0
3 years ago
1. Solve for x 3(x-6)+24=50+4(x+10)
MA_775_DIABLO [31]
X=-84. 3(x-6)+24=50+4(x+10)
distrubute. 3x-18+24=50+4x+40
move terms. 3x+6=90+4x
collect like terms 3x-4x=90-6
subtract -x=84
divide by -1. x=-84
3 0
2 years ago
How to find the derivative of cos^2x? i seem to be confused.
slamgirl [31]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2927231

————————

You can actually use either the product rule or the chain rule for this one. Observe:

•  Method I:

y = cos² x

y = cos x · cos x


Differentiate it by applying the product rule:

\mathsf{\dfrac{dy}{dx}=\dfrac{d}{dx}(cos\,x\cdot cos\,x)}\\\\\\
\mathsf{\dfrac{dy}{dx}=\dfrac{d}{dx}(cos\,x)\cdot cos\,x+cos\,x\cdot \dfrac{d}{dx}(cos\,x)}


The derivative of  cos x  is  – sin x. So you have

\mathsf{\dfrac{dy}{dx}=(-sin\,x)\cdot cos\,x+cos\,x\cdot (-sin\,x)}\\\\\\
\mathsf{\dfrac{dy}{dx}=-sin\,x\cdot cos\,x-cos\,x\cdot sin\,x}


\therefore~~\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=-2\,sin\,x\cdot cos\,x}\end{array}}\qquad\quad\checkmark

—————

•  Method II:

You can also treat  y  as a composite function:

\left\{\!
\begin{array}{l}
\mathsf{y=u^2}\\\\
\mathsf{u=cos\,x}
\end{array}
\right.


and then, differentiate  y  by applying the chain rule:

\mathsf{\dfrac{dy}{dx}=\dfrac{dy}{du}\cdot \dfrac{du}{dx}}\\\\\\
\mathsf{\dfrac{dy}{dx}=\dfrac{d}{du}(u^2)\cdot \dfrac{d}{dx}(cos\,x)}


For that first derivative with respect to  u, just use the power rule, then you have

\mathsf{\dfrac{dy}{dx}=2u^{2-1}\cdot \dfrac{d}{dx}(cos\,x)}\\\\\\
\mathsf{\dfrac{dy}{dx}=2u\cdot (-sin\,x)\qquad\quad (but~~u=cos\,x)}\\\\\\
\mathsf{\dfrac{dy}{dx}=2\,cos\,x\cdot (-sin\,x)}


and then you get the same answer:

\therefore~~\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=-2\,sin\,x\cdot cos\,x}\end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>derivative chain rule product rule composite function trigonometric trig squared cosine cos differential integral calculus</em>

3 0
3 years ago
Solve 6^x=1,296<br><br><br> X=__________a0
Troyanec [42]

Answer:

x=4

Step-by-step explanation:

6^x = 1296

Take the log base 6 on each side

log6(6^x) = log6(1296)

Rewrite 1296 as 6^4

x = log 6(6^4)

We know that log( a^b) = b log (a)

x = 4 log6(6)

We know that loga(a) =1

x = 4 *a

x =4

5 0
2 years ago
Read 2 more answers
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