Check the picture below.
so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?
now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2 = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.
![\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%20in%20feet%7D%20%5C%5C%5C%5C%20h%28x%29%20%3D%20-16x%5E2%2Bv_ox%2Bh_o%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Ctextit%7Binitial%20velocity%7D%260%5C%5C%20%5Cqquad%20%5Ctextit%7Bof%20the%20object%7D%5C%5C%20h_o%3D%5Ctextit%7Binitial%20height%7D%26%5C%5C%20%5Cqquad%20%5Ctextit%7Bof%20the%20object%7D%5C%5C%20h%3D%5Ctextit%7Bobject%27s%20height%7D%260%5C%5C%20%5Cqquad%20%5Ctextit%7Bat%20%22t%22%20seconds%7D%5C%5C%20x%3D%5Ctextit%7Bseconds%7D%261%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%200%3D-16%281%29%5E2%2B0x%2Bh_o%5Cimplies%200%3D-16%2Bh_o%5Cimplies%2016%3Dh_o%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20h%28x%29%20%3D%20-16x%5E2%2B16~%5Chfill)
quick info:
in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².
Answer:
-3
Step-by-step explanation:
In the slope-intercept form of linear equation (y=mx+b) the slope is the number next to the x, here represented with the letter m. In your equation, y =-3x+7, the m is replaced by -3, so the slope here is -3.
Using iready the tutorial does not count as a grade and if your worried about passing the test turn your wifi off count to 10 then click the answer you think is right, if it is right turn wifi back on and click next, if wrong click next and it will kick you out of it then turn wifi back on and go back onto the lesson and repeat until you have the right answer, I always got 100% on my quizs this way
Answer:
Area 1 is the best option
Step-by-step explanation:
Given Data:
Area 1 = 0.75 dam square
Price = €11,620
Area 2 = 0.009 ha
at €193,500
Area 3 = 0.84a
at €68,900
Where ha ( hectare )
a ( area )
Solution
First we convert all areas to square meter ( m² )
Area 1 = 100 * 0.75 dam square
= 75m²
Cost of area 1/ square meter
= €11,620 / 75m²
= €154.93 / square meter
Area 2 = 0.009 ha * 10,000
= 90m²
Cost of area 2 / square meter
= €193,500 / 90m²
= €2,150 / square meter
Area 3 = 0.84a * 100
= 84m²
= Cost of area 3 / square meter
= €68,900 / 84m²
= €820.23 / square meter
