Can anyone help me with this math problem real quick please
2 answers:
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Answer:
x= 4 and y=1
Step-by-step explanation:
to solve this you could either use substitution or elimination. elimination would be best her because both 'x's have the same number. subtract the equations from eahh other and solve for y, then substitute the y and solve for x
Answer:
This is approximately the same as
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Explanation:
Solve the given equation for y
5x-y = 1
-y = -5x+1
y = 5x-1
slope of this line is m = 5 since it is in the form y = mx+b
Write m = 5 as m = 5/1
Flip the fraction: 5/1 ----> 1/5
Flip the sign: 1/5 ----> -1/5
The perpendicular slope is -1/5
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Let p and q be the x and y intercepts
So the equation we're after goes through the points (p,0) and (0,q)
The slope of the line through these points is
m = (y2-y1)/(x2-x1)
m = (q-0)/(0-p)
m = q/(-p)
m = -q/p
We want this slope to be -1/5 as this is the perpendicular slope we found earlier
-q/p = -1/5
q/p = 1/5
5q = 1p
p = 5q ... we will use this later
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The base of the triangle is p while the height is q
We want the area of the triangle to be 5 square units
area = 0.5*base*height
5 = 0.5*p*q
5 = 0.5*(5q)*q ... plug in p = 5q
5 = 2.5q^2
2.5q^2 = 5
q^2 = 5/2.5
q^2 = 2
q = sqrt(2)
p = 5*q
p = 5*sqrt(2)
The y intercept is b = q = sqrt(2), so
y = mx+b
See the diagram below.
