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Pachacha [2.7K]
2 years ago
8

Find the inverse of the Function

0-4" id="TexFormula1" title="f(x)=\sqrt[3]{\frac{x}{9} } -4" alt="f(x)=\sqrt[3]{\frac{x}{9} } -4" align="absmiddle" class="latex-formula">

Mathematics
1 answer:
scoray [572]2 years ago
6 0

9514 1404 393

Answer:

  D

Step-by-step explanation:

Solve x = f(y) for y.

  x = ∛(y/9) -4

  x +4 = ∛(y/9) . . . . . add 4

  (x +4)³ = y/9 .. . . . . cube

  9(x +4)³ = y . . . . . . multiply by 9

The inverse function is ...

  f⁻¹(x) = 9(x +4)³ . . . . . matches the last choice

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3 years ago
If y=24 when x=21, find y when x is 18
ludmilkaskok [199]

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Step-by-step explanation:

x:y = 21: 24=7:8

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y=8x/7

When x=18

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3 years ago
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Sloan [31]

Answer:

Sum of \frac{7x}{x^2-4} and \frac{2}{x+2} is \mathbf{\frac{9x-4}{x^2-4}}

Option B is correct answer.

Step-by-step explanation:

We need to find sum of \frac{7x}{x^2-4} and \frac{2}{x+2}

Finding sum of  \frac{7}{x^2-4} and \frac{2}{x+2}:

\frac{7x}{x^2-4}+\frac{2}{x+2}

We know that x^2-4 =(x+2)(x-2)

Replacing x^2-4

\frac{7x}{(x+2)(x-2)}+\frac{2}{x+2}

Now, taking LCM of (x+2)(x-2) and (x+2) we get (x+2)(x-2)

=\frac{7x+2(x-2)}{(x+2)(x-2)}\\=\frac{7x+2x-4}{(x+2)(x-2)}\\=\frac{9x-4}{(x+2)(x-2)}\\=\frac{9x-4}{x^2-4}

So, Sum of \frac{7x}{x^2-4} and \frac{2}{x+2} is \mathbf{\frac{9x-4}{x^2-4}}

Option B is correct answer.

6 0
2 years ago
How do you solve this problem
dmitriy555 [2]

Answer:

4.5 in

Step-by-step explanation:

IT si 4.5 inches because the scale factor is 1 inch to 4 feet, and 18/4 = 4.5 inches.

5 0
3 years ago
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