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3 years ago

What is the equation of the graph below?

Mathematics

1 answer:

Alik [6]3 years ago

5 0

So by looking at the graph you can see it is cos since it dosent start at (0,0). Then since there is a phase shift of what looks like 90 to the left makes the equation y=cos(x+90)

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URGENT!!! WILL MARK BRAINLIEST!<br> Find the measure of Angle DBE then find the measure of ∠ABD?

dedylja [7]

Answer:

m<DBE =50°

m<ABD=150°

Step-by-step explanation:

Because of Straight Angles, All the angles will add up to 180 degrees

Let x be m<DBE

40+x+70+20=180

x+130=180

x=50

m<DBE will be 50 degrees

To find the m<ABD, we add m<FBA, m<FBE, m<DBE.

70+50+30=150

m<ABD = 150

7 0

3 years ago

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Fofino [41]

$Domain:x\neq-3\\\\\dfrac{2x}{x+3}\leq3\qquad\text{subtract 3 from both sides}\\\\\dfrac{2x}{x+3}-3\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3(x+3)}{x+3}\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3x+9}{x+3}\leq0\\\\\dfrac{2x-(3x+9)}{x+3}\leq0\\\\\dfrac{2x-3x-9}{x+3}\leq0\\\\\dfrac{-x-9}{x+3}\leq0\Rightarrow(x+3)(-x-9)\leq0\\\\x=-3,\ x=-9\\\\x\in(-\infty,\ -9]\ \cup\ (-3,\ \infty)$

3 0

3 years ago

Identify the whole numbers in the list: 4, 3.14, -2.2, 11, 0

Vlad1618 [11]

The whole numbers in this list are 4, 11, 0, I hoped this helped :)

8 0

3 years ago

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Irum is sitting on the beach, watching the tide go in and out. Irum's distance from the shoreline (in meters) as a function of t

Nesterboy [21]

Answer:

Hi, the Answer is 0.75.

Step-by-step explanation:

it is 0.75 because if you look on the graph, and you calculate the 3/4 slope between the two, 3/4= 0.75

4 0

3 years ago

Find the approximate mean and standard deviation of the following data.

Makovka662 [10]

Given the data in the table, to find the approximate mean we would need to find the midpoints for the given intervals.

The midpoint was gotten from the average of the upper and lower class intervals.

We can then find the approximate mean using the formula below.

$\bar{x}(Mean)=\frac{\sum^{}_{}fx}{\sum^{}_{}f}$

Therefore,

$\begin{gathered} \bar{x}=\frac{(8\times3.5)+(11.5\times3)+(19.5\times9)+(27.5\times5)}{8+3+9+5} \\ \bar{x}=\frac{28+34.5+175.5+137.5}{25} \\ \bar{x}=\frac{375.5}{25} \\ \bar{x}=15.02 \end{gathered}$

To find the standard deviation we would use the formula below;

$\begin{gathered} \sigma^2=\frac{\sum^{}_{}f(x-\bar{x})^2}{\sum^{}_{}f} \\ ^{} \end{gathered}$

Thus;

$\begin{gathered} \sigma^2=\frac{8(3.5-15.02)^2+3(11.5-15.02)^2+9(19.5-15.02)^2+5(27.5-15.02)^2}{25} \\ =\frac{1061.6832+37.1712+180.6336+778.752}{25} \\ \sigma^2=82.3296 \\ \sigma=\sqrt[]{82.3296} \\ \sigma=9.074 \end{gathered}$

Answer:

Therefore, the approximate mean and standard deviation is 15.02 and 9.074 respectively

4 0

1 year ago