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nikitadnepr [17]
3 years ago
12

If r = 1 and θ = 4π/3 what is the approximate arc length

Mathematics
2 answers:
MatroZZZ [7]3 years ago
7 0

Answer: 4.189 units

Step-by-step explanation:

AP EX

Artist 52 [7]3 years ago
5 0

Answer: arc length = r * θ = (3 in) * (135°) = (3 in) * (3π / 4 rad) = 9π / 4 in.

Step-by-step explanation:

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2/3 x + 5/6 = x - 1/2<br><br><br><br><br> SHOW WORK PLEASE
Digiron [165]

Answer:

x=4

Step-by-step explanation:

2/3 x + 5/6 = x - 1/2

Multiply each side by 6 to clear the fractions

6(2/3 x + 5/6) = 6(x - 1/2)

Distribute

4x +5 = 6x-3

Subtract 4x from each side

4x+5 -4x = 6x-3-4x

5 = 2x-3

Add 3 to each side

5+3= 2x-3+3

8 =2x

Divide by 2

8/2 =2x/2

4 =x

5 0
3 years ago
Read 2 more answers
A trapezoid has an area of 150 square meters . If the bases are 14 meters and 16 meters, what is the height of the trapezoid?
Mariana [72]
H= 10m

Hope this helps
5 0
3 years ago
I will mark you brainliest!!!! Which ordered pair is the best approximation of the solution?
Ulleksa [173]

Answer:

D

Step-by-step explanation:

We can substitute y = 2x + 1 in the second equation

2x + 1 = -7x + 8

Add 7x to both sides

9x + 1 = 8

Subtact 1 from both sides

9x = 7

x = 7/9

Substituing x in the first equation

y = 14/9 + 1

x rounds to 0.8

y rounds to 2.5

 

5 0
3 years ago
Roger has a credit card with an APR of 19.40% and a billing cycle of 30 days. The following table shows his transactions with th
Allushta [10]

Answer:

The daily balance method

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Peter runs laps on the school track every afternoon. He wants to run no more than 60 minutes a day. He can consistently run each
abruzzese [7]

Answer:

1.5x ≤ 60

Step-by-step explanation:

He wants to run no more than 60 minutes a day

No more than means Less than or equal to with the inequality sign of ≤

Each lap = 1.5 minutes.

The greatest number of laps Peter could run = x

Therefore, the inequality that best represents the situation and represents x, the greatest number of laps Peter could run in a day

1.5 × x ≤ 60 minutes

= 1.5x ≤ 60

Solving for x

1.5x ≤ 60

x ≤ 60/1.5

x ≤ 40 laps

Hence, the Greatest number of laps = x that he can run is 40 laps

4 0
3 years ago
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