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GarryVolchara [31]
2 years ago
5

8x^3-8x=1 Solve for x

Mathematics
1 answer:
Anit [1.1K]2 years ago
4 0

Step-by-step explanation:

Step-by-step explanation:

\begin{gathered} \frac{8x - 3}{3x} = 2 \\ 8x - 3 = 6x \\ 8x - 6x = 3 \\ 2x = 3 \\ x = \frac{3}{2} \end{gathered}

3x

8x−3

=2

8x−3=6x

8x−6x=3

2x=3

x=

2

3

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Answer:

1)The rocket hit the ground at     x = \frac{5}{4}

2)The maximum height of the rocket = 12.468 feet

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equation  

                y = -2 x² + 5 x + 7 ...(i)

Differentiating equation (i) with respective to 'x' , we get

             \frac{dy}{dx} = -2( 2x) +5(1) =  -4x +5

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            \frac{dy}{dx} = 0

⇒      -4 x +5 =0

⇒      -4 x = -5

⇒          x = \frac{5}{4}

<em> The rocket hit the ground at     </em>x = \frac{5}{4}<em></em>

<u><em>Step(ii):</em></u>-

    \frac{dy}{dx}  =  -4x +5  ...(ii)

Again differentiating equation (ii) with respective to 'x' , we get

 \frac{d^{2} y}{dx^{2} }  = - 4(1)

The maximum height at x = \frac{-5}{4}

  y = -2 x² + 5 x + 7

 y = -2 (\frac{5}{4})^{2}  + 5 (\frac{5}{4} )  + 7

y = \frac{-2(25)+ 25 (16)+7(64)}{64}

y = \frac{798}{64} = 12.468 feet

<em>The maximum height of the rocket = 12.468 feet</em>

       

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