Answer:
Equation of tangent plane to given parametric equation is:
Step-by-step explanation:
Given equation
---(1)
Normal vector tangent to plane is:
Normal vector tangent to plane is given by:
Expanding with first row
at u=5, v =π/3
---(2)
at u=5, v =π/3 (1) becomes,
From above eq coordinates of r₀ can be found as:
From (2) coordinates of normal vector can be found as
Equation of tangent line can be found as:
Answer C
steps
deduct 10 from 26
26-10 which will give us 16
2500
50020%50020%
Convert 20%20% to a decimal.
5000.25000.2
Divide 500500 by 0.20.2.
Area =
=》
Area = 40 in²