The value of the cosine ratio cos(L) is 5/13
<h3>How to determine the cosine ratio?</h3>
The complete question is added as an attachment
Start by calculating the hypotenuse (h) using
h^2 = 5^2 + 12^2
Evaluate the exponent
h^2 = 25 + 144
Evaluate the sum
h^2 = 169
Evaluate the exponent of both sides
h = 13
The cosine ratio is then calculated as:
cos(L) = KL/h
This gives
cos(L) =5/13
Hence, the value of the cosine ratio cos(L) is 5/13
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1. The mean is calculated using:
(9.4 + 17 + 7.3 + 7 + 16.1 + 5.4 + 5.9 + 8.5 + 4.2 + 9.2)/ 10
= 9
2. The standard deviation is 4.31
3. The years are 1996, 1997, 1999-200
<span>c) 1996 and 1997
</span>
4. The median is 7.9
Five times the sum of x and negative two, or five times the difference of x and two
Answer:
Step-by-step explanation:
(f*g)(x) = (-5x² + 2x + 7) (x +1)
= x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)
= x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7
= -5x³ + 2x² + 7x - 5x² + 2x + 7
= - 5x³ + <u>2x² -5x²</u> <u>+ 7x + 2x </u>+7 {Combine like terms}
= -5x³ - 3x² + 9x + 7
4) (f*g)(x) = (x² + 2x + 4)(x - 2)
= x*(x² + 2x + 4) - 2*(x² + 2x + 4)
= x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4
= x³ + 2x² + 4x -2x² -4x - 8
= x³ - 8


Answer:7^6
Step-by-step explanation: