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3 years ago

6

A large van is being used for a picnic. There will be 8 people riding in the van, and there are 8 seats in the van (one of which

is the driver's seat). One of the 8 people will have to drive, but only 4 of the people are licensed to drive the van. In how many different ways could the people seat themselves in the van so that they have a licensed driver

1 answer:

Julli [10]3 years ago

6 0

Answer:

The people can seat themselves in 20160 different ways.

Step-by-step explanation:

Arrangements of n elements:

The number of arrangements of n elements is given by the following formula:

$A_{n} = n!$

In this question:

For the first seat, that is, the driver seat, 4 possible people can sit.

For the remaining 7 seats, the number of ways in which the people can sit is an arrangement of 7 elements. So

$T = 4*7! = 4*5040 = 20160$

The people can seat themselves in 20160 different ways.

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The quick way to do this is to multiply the bill by 1, mult. it again by 0.18, and then add the two results together.

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A vase can hold 9 flowers. If a florist had 878 flowers she wanted to put equally into vases, how many flowers would be in the l

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Add the two expressions.<br><br> 3z−4 and 2z + 5<br><br> Enter your answer in the box.

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Find the missing exponent in each expression

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Answer:

See below.

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Multiplying terms with exponents make the exponents add together.

13.) x² · x⁵ = x⁷

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

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Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

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