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Brut [27]
2 years ago
13

2x + 4 = 10? ,A) 4 ,B) 5 ,C) 7 ,D) 3​

Mathematics
1 answer:
Sergio039 [100]2 years ago
6 0

Answer:

D) 3

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplications

Divisions

Additions

Subtractions

~

First, subtract 4 from both sides of the equation:

2x + 4 (-4) = 10 (-4)

2x = 10 - 4

2x = 6

Next, divide 2 from both sides of the equation:

(2x)/2 = (6)/2

x = 6/2

x = 3

D) 3 is your answer.

~

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2. Find the common difference and the recursive formula. a. 22, 19, 16, 13, …
Musya8 [376]

Answer:

The common difference d is d = -3

The recursive formula is: \mathbf{a_n=a_{n-1}-3}

Step-by-step explanation:

We need to find the common difference and the recursive formula.

a. 22, 19, 16, 13, …

First we will find common difference

The formula of arithmetic sequence is: a_n=a_1+(n-1)d

where a_n is nth term, a_1 is 1st term and d is the difference

Looking at the sequence we get: a_1=22, a_2=19

Using these values we can find d, the common difference

a_n=a_1+(n-1)d\\put\:n=2, a_2=19, a_1=22\\19=22+(2-1)d\\19=22+d\\d=19-22\\d=-3

So, the common difference d is d = -3

Now, we will find the recursive formula:

The recursive formula is of type: a_n=a_{n-1}+d

We have found common difference d = -3

So, the recursive formula will be:

a_n=a_{n-1}+d\\a_n=a_{n-1}+(-3)\\a_n=a_{n-1}-3

The recursive formula is: \mathbf{a_n=a_{n-1}-3}

6 0
3 years ago
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lidiya [134]
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Answer:

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