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lys-0071 [83]
3 years ago
13

Which equation when graphed is not a straight line (is nonlinear)

Mathematics
1 answer:
kompoz [17]3 years ago
5 0

Answer  for this question you have to graph  it

Step-by-step explanation:

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Find the missing length indicated.<br> ?<br> 12<br> 4<br> 9<br> 28<br> 50<br> 12.
bekas [8.4K]

Answer:

28 probably sorry if wrong

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What is the total cost of 1.2 Cubic yards of soil if it sells for $24 per cubic yard?
Kaylis [27]

Answer:

$28.80 I hope that helps if not I'm sorry if it's wrong

Step-by-step explanation:

we write "dollars per cubic yard" as "dollars/yd^3" so that the units "yd^3" will cancel when multiplying by "1.2 yd^3", leaving an answer in units of dollars

24 dollars / yd^3 * 1.2 yd^3 = 28.80

the cost would be $28.80

6 0
3 years ago
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Proof sin^3xcos^4x=sinx(cos^4x-cos^6x)
Alina [70]
Sin³(x)cos⁴(x) = sin(x)[cos⁴(x) - cos⁶(x)]
      sin(x)                         sin(x)
sin²(x)cos⁴(x) = cos⁴(x) - cos⁶(x)
sin²(x)cos⁴(x) = cos⁴(x)[1] - cos⁴(x)[cos²(x)]
sin²(x)cos⁴(x) = cos⁴(x)[1 - cos²(x)}
     cos⁴(x)                  cos⁴(x)
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       + cos²(x)      + cos²(x)
                    1 = 1
8 0
3 years ago
Multiply using an area model or the distributive property. "So my question is how do I put this."
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.73 times 3

cmon now thats common knowledge
7 0
4 years ago
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Select the functions that have a value of -1. sin180° cos180° tan180° csc180° sec180° cot180°
kupik [55]

We have to break each degree in terms of 90

A) sin180^\circ=sin(90\times2+0)

Which is in third quadrant, therefore sine is negative hence

sin(90\times2+0)= -sin0 ^\circ = 0


B) cos180^\circ =cos(90\times2+0)

Which is in third quadrant, therefore cosine is negative hence

cos(90\times2+0)= -cos0^\circ  = -1


C) tan180^\circ=tan(90\times2+0)

Which is in third quadrant, therefore tangent is positive hence

tan(90\times2+0)= tan0^\circ  = 0


D) csc180^\circ=csc(90\times2+0)

Which is in third quadrant, therefore cosec is negative hence

cosec(90\times2+0)= -csc0^\circ  =not defined


E)sec180^\circ=sec(90\times2+0)

Which is in third quadrant, therefore secant is negative hence

sec(90\times2+0)= -sec0^\circ  = -1


F) cot180^\circ=cot(90\times2+0)

Which is in third quadrant, therefore tangent is positive hence

cot(90\times2+0)= cot0^\circ = not defined


Hence only cos 180^\circ and

sec180^\circ have value -1

Hope this will help

7 0
3 years ago
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