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3 years ago

Which equation when graphed is not a straight line (is nonlinear)

Mathematics

1 answer:

kompoz [17]3 years ago

5 0

Answer for this question you have to graph it

Step-by-step explanation:

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Catherine sketched the slope triangle on the previous slide. Notices that the slope triangle has a 2 and 4, so she thinks the sl

Liula [17]

Answer:

1/2

Step-by-step explanation:

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3 years ago

HELP PLEASE!!!!!!!!!!!

Elza [17]

Step-by-step explanation:

1)y=17-2=15

2)y=17-6=11

3)y=17-8=9

4y=17-10=7

6 0

3 years ago

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Apply the Pythagorean Theorem to find the distance between points A and C.

galina1969 [7]

Answer:

So the correct option is C ) 58 units.

Also If we require Distance then l(AC) = √58 = 7.615 units

Step-by-step explanation:

Let the Points be

point A( x₁ , y₁) ≡ ( -2 , 1)

point C( x₂ , y₂) ≡ (5 , -2)

To Find:

d(AC) = ?

Solution:

By Applying the Pythagorean Theorem to find the distance between points A and C we get

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting A( x₁ , y₁) ≡ ( -2 , 1) and C( x₂ , y₂) ≡ (5 , -2) we get

$l(AC) = \sqrt{((5-{(-2}))^{2}+(-2-1)^{2} )}\\\\l(AC) = \sqrt{(5+2)^{2}+(-3)^{2}}\\\\l(AC) = \sqrt{(49+9)}\\\\l(AC) = \sqrt{58}\\\\OR\\l(AC)^{2} = 58\ units$

So the correct option is C ) 58 units.

If we require Distance then l(AC) = √58 = 7.615 units

8 0

3 years ago

Canadian provinces by population density

Savatey [412]

Not quite sure what the question being asked here is.

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3 years ago

Will give brainliest

klemol [59]

Your question is calling the figure ABCD, but the image is showing PQRS

Using the letters that you wrote:

Because the figure was only rotated and not scaled , the sides with the same letters would still be the same

So AB would be the same as A'B' ( Length of AB = Length of A′B)

and

BC = B'C'

CD = C'D'

AD = A'D'

Or by the picture:

PQ = P'Q'

QR = Q'R'

RS = R'S'

PS = P'S'

7 0

3 years ago

Read 2 more answers