Multiply using an area model or the distributive property. "So my question is how do I put this."

Mathematics

2 answers:

Leni [432]4 years ago

7 0

.73 times 3

cmon now thats common knowledge

iVinArrow [24]4 years ago

6 0

Let x be the number of markers.
Equation: 0.73(x)
So since we want the cost of 3 markers, plug it into the equation to get:
0.73(3)=2.19

Answer: $2.19

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The price of an item yesterday was $120. Today, the price fell to $78

marusya05 [52]

Answer:

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8 0

2 years ago

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The graph of F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x). If F(x) = x2, which of t

kherson [118]

If we want to stretch graph vertically we need to multiply function f(x) with a number greater than 1. By doing so we will for same difference of x get larger difference of F(x) which means function will be stretched.

If we want to flipp over x axis function F(x) all we need to do is to multiply it by -1. Function will change its sign thus for same values of x we will get value of F(x) with oposite sign which means function will be flipped over x axis.

Looking at offered answers we can say that A and B arent answer because we didnt multiply function with number greater than 1.

Answer is C) G(x) = -4x^2

4 0

4 years ago

NO LINKS!! Please help me with this problem

12345 [234]

Answer:

$\frac{x^2}{784}+\frac{y^2}{400}=1$

Step-by-step explanation:

Horizontal Major Axis:

$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}$

Vertical Major Axis:

$\frac{(y-k)^2}{a^2}+\frac{(x-h)^2}{b^2}+$

So these two expressions are essentially the same with the only difference being the location of "a" and "b". The length of the major axis will be "2a" and the length of the minor axis will be "2b". The way I remember this is because when you have the horizontal major axis the "a" value is in the denominator of the (x-h) and I think of "x" as a horizontal value, since it moves a point horizontally. When you have a vertical major axis the "a" value is in the denominator of (y-k) and I think of "x" as a vertical value, since it moves a point vertically.

So just by looking at the graph, you can easily determine that the eclipse has a horizontal major axis. This can be further proven, since the distance from the origin on the right side is 28, and the distance from the the top to the origin is only 20.

So you could set up an equation to solve for a, since 2a = length of major axis, but since we're given the two points, the "a" value is really just the length from the origin to the right/left side, and combining these together you get the value of 2a/major axis, but you don't have to do that. So by looking at the graph you'll see the distance from the origin to the right side is 28. This means "a=28"

You can do the same thing here for the "b" value, and since the top is 20 units away from the origin, "b = 20"

So now let's set up the equation:
$\frac{x^2}{28^2} + \frac{y^2}{20^2}=1$