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3 years ago

Why the Modern dry process is preferred to another conventional process?

1 answer:

3 0

It can reduce heat loss by heating water. Also plants are based on the dry process, and it’s much better for the environment rather than any other conventional process.

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Ammonium hydroxide is neutralized by sulfuric acid to produce ammonium sulfate and water. It will make ___ mol ammonium sulfate

Bingel [31]

Answer:

1) Ammonium hydroxide is neutralized by sulfuric acid to produce ammonium sulfate and water. It will make 0.157 mol ammonium sulfate when you neutralize 11.00 g ammonium hydroxide.

2) 2NH₄OH + H₂SO₄ → (NH₄)₂SO₄ + 2H₂O.

Explanation:

Firstly, we should balance the equation of heptane combustion.
We can balance the equation by applying the conservation of mass to the equation.

The balanced equation is: 2NH₄OH + H₂SO₄ → (NH₄)₂SO₄ + 2H₂O.

This means that every 2.0 moles of ammonium hydroxide (NH₄OH) will produce 1.0 mole of ammonium sulfate (NH₄)₂SO₄ when it is neutralized by sulfuric acid.

We need to calculate the no. of moles in 11.0 g of ammonium hydroxide that is neutralized using the relation: n = mass/molar mass.

n of 11.0 g of ammonium hydroxide (NH₄OH) = mass/molar mass = (11.0 g)/(35.04 g/mol) = 0.314 mol.

Using cross multiplication:

2.0 moles of NH₄OH make → 1.0 mole of (NH₄)₂SO₄.

0.314 mol of NH₄OH make → ??? moles of (NH₄)₂SO₄.

∴ The no. of moles of (NH₄)₂SO₄ that will be made from neutralizing (11.0 g) of NH₄OH = (0.314 mol)(1.0 mol)/(2.0 mol) = 0.157 mol.

∴ Ammonium hydroxide is neutralized by sulfuric acid to produce ammonium sulfate and water. It will make 0.157 mol ammonium sulfate when you neutralize 11.00 g ammonium hydroxide.

3 0

4 years ago

A 0.1014 g sample of a purified compound containing C, H, and, O was burned in a combustion apparatus and produced 0.1486 g CO2

Alina [70]

Answer: The empirical formula for the given compound is $CH_2O$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=0.1486g$

Mass of $H_2O=0.0609g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.1486 g of carbon dioxide, $\frac{12}{44}\times 0.1486=0.0405g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0609 g of water, $\frac{2}{18}\times 0.0609=0.00677$ of hydrogen will be contained.

Mass of oxygen in the compound = (0.1014) - (0.0405 + 0.00677) = 0.054 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0405g}{12g/mole}=0.003375moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.00677g}{1g/mole}=0.00677moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.054g}{16g/mole}=0.003375moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.485 moles.

For Carbon = $\frac{0.003375}{0.003375}=1$

For Hydrogen = $\frac{0.00677}{0.003375}=2.00\times 2$

For Oxygen = $\frac{0.003375}{0.003375}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 2 : 1

The empirical formula for the given compound is $C_1H_2O_1=CH_2O$

Thus, the empirical formula for the given compound is $CH_2O$

8 0

3 years ago

The Earth's winds are caused by uneven heating of the atmosphere by solar radiation. The uneven heating causes air masses to hav

ozzi

Warmer, less dense air masses rise in the atmosphere; colder, denser air masses sink in the atmosphere.

hopes this helps chu

3 0

4 years ago

Read 2 more answers

Pyridine is a weak base that is used in the manufacture of pesticides and plastic resins. It is also a component of cigarette sm

Luda [366]

Answer:

pH of the solution = 9.45

Explanation:

pKb = 8.57

pKb = -logKb

Kb = antilog pkb

$K_b = 1.78 \times 10^{-9}$

ICE table for the ionization of pyrodine is:

$C_5H_5N+H_2O \leftrightharpoons C_5H_5NH^+ + OH^-$

initial 0.435 0 0

equi. 0.435 - x x x

so,

$k_b =\frac{ [C_5H_5NH^+][OH^-]}{[C_5H_5N]}\\1.78\times 10^{-9}=\frac{x^2}{0.453 - x}$

As kb is very less that means there is very less ionization, hence x can be ignored as compared to 0.435

$x^2 = 1.78\times 10{-9} \times 0.435\\x= 2.78\times 10^{-5}$

pOH = -log[OH-]

$pOH = -log[2.78\times 10^{-5}]\\=4.55$

pH = 14 - pOH

= 14 - 4.55

= 9.45

5 0

4 years ago

Organelles that use energy from sunlight to produce food are called mitochondria

arsen [322]

Answer:

Organelles that use energy from sunlight to produce food are called mitochondria.

False

3 0

3 years ago

Why the Modern dry process is preferred to another conventional process? ​

Why the Modern dry process is preferred to another conventional process?