The limiting reagent when 5 g of NaOH and 4.4 g CO₂ allowed to react will be NaOH
<h3>What is Limiting reagent ?</h3>
The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.
Given chemical equation in balanced form ;
2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l).
According to the Chemical equation ;
- The limiting reagent when 5 g of NaOH and 4.4 g CO₂ allowed to react will be NaOH
If 44 g CO₂ requires 80 g of NaOH, therefore, 4.4 g CO₂ will require atleast 8 g of NaOH.
But the available quantity is 5 g NaOH. thus, NaOH is the Limiting reagent.
- 6.625 g of Na₂CO₃ are expected to be produced 5.0 g of NaOH and 4.4 g of CO₂ are allowed to react
As 80 g NaOH produces 106 g of Na₂CO₃.
Therefore 5 g NaoH will produce ;
106 / 80 x 5 = 6.625 g
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Answer:
<h2>chemoautotrophs</h2>
Explanation:
Such types of bacteria that oxidize inorganic compounds to obtain energy and use carbon dioxide as a carbon source to synthesize their food are known as chemoautotrophs such as iron-oxidizing bacteria, cyanobacteria, sulfur-oxidizing bacteria and some other. Chemoautrophic mode of nutrition is a type of autotrophic nutrition in which organisms have the ability to synthesized their own food by using chemical energy in the place of solar energy. The organismS that use solar energy to synthesize their food are known as photoautotrophic organisms such as plants and some other organisms.
The pencil attached to the negative terminal of the battery collects hydrogen gas while the one connected to the positive terminal collects oxygen.
Answer:
0.0249 moles in 1 g of Ca
Explanation:
Let's think in the molar mass of Ca.
Ca = 40.08 g/mol
So 1 mol weighs 40.08 grams, or in the opposite 40.08 grams is the weigh of 1 mol
The rule of three will be:
40.08 g are contained in 1 mol
1 g may be contained in (1 . 1) / 40.08 = 0.0249 moles
Answer:
Wowww this is cool did you draw this?
Explanation:
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