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2 years ago

Pleasee helppp insert two arithnetic means between -5 and 1

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

3 0

Answer:

a₂ = -3

a₃ = -1

Step-by-step explanation:

We have to insert two arithmetic means between -5 and 1

Let a₁ and b₂ be the two arithmetic means between -5 and 1

-5, a₂, a₃, 1

Here,

a₄ = 1

a₁ = -5

We know that the nth term of an Arithmetic sequence

aₙ = a₁ + (n-1)d

a₄ = -5 + (4-1)d

1 = -5 + 3d

1 + 5 = 3d

3d = 6

Dividing both sides by 2

d = 2

Also

a₂ = a₁ + (2-1)d

a₂ = -5 + d

a₂ = -5 + 2 ∵ d = 2

a₂ = -3

a₃ = a₁ + (3-1)d

a₃ = -5 + 2d

a₃ = -5 + 2(2) ∵ d = 2

a₃ = -5 + 4

a₃ = -1

Thus,

a₂ = -3

a₃ = -1

Thus, the sequence becomes:

-5, -3, -3, 1

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Which equation is true when x = 5? A 8x = 80 B x + 4 = 9 C 10 ÷ x = 5 D x − 6= 1

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Answer:

Step-by-step explanation:

A. 8 * x = 80

8 * 5 = 40. 40 is not 80, so it doesn't work.

B. x + 4 = 9

5 + 4 = 9. This works.

C. 10 ÷ x = 5

10 ÷ 5 = 2. 5 is not 2, so it doesn't work.

D. x - 6 = 1

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2 years ago

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Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

According to the Figure Given:

Total Horizontal Distance = 14 in

Length = 6 in

To Find :

The Area of the composite figure

Solution:

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

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