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2 years ago

Pleasee helppp insert two arithnetic means between -5 and 1

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

3 0

Answer:

a₂ = -3

a₃ = -1

Step-by-step explanation:

We have to insert two arithmetic means between -5 and 1

Let a₁ and b₂ be the two arithmetic means between -5 and 1

-5, a₂, a₃, 1

Here,

a₄ = 1

a₁ = -5

We know that the nth term of an Arithmetic sequence

aₙ = a₁ + (n-1)d

a₄ = -5 + (4-1)d

1 = -5 + 3d

1 + 5 = 3d

3d = 6

Dividing both sides by 2

d = 2

Also

a₂ = a₁ + (2-1)d

a₂ = -5 + d

a₂ = -5 + 2 ∵ d = 2

a₂ = -3

a₃ = a₁ + (3-1)d

a₃ = -5 + 2d

a₃ = -5 + 2(2) ∵ d = 2

a₃ = -5 + 4

a₃ = -1

Thus,

a₂ = -3

a₃ = -1

Thus, the sequence becomes:

-5, -3, -3, 1

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Fred Salmon purchased six $1,000 bonds at 92. The bonds pay 6.5%, what is the cost of the bonds

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The cost of the bond
6×1,000×0.92=5,520

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3 years ago

Read 2 more answers

Solve by using any method of substitution<br><br>4 +8x = y <br>6x - y = 2

Bumek [7]

Answer:

(-3,-20)

Step-by-step explanation:

4 +8x = y ...... equation (1)

6x - y = 2 ........equation(2)

from equation 2

6x - y = 2

6x -(4+8x) =2

6x - 4 + 8x = 2

+4 +4

6x - 8x = 6

-2x=6

divide by -2

x= -3

put x in equation (1) to solve for y

4 + 8x = y

4+8(-3)=y

4-24=y

-20=y

y= -20

solution = (-3,-20)

8 0

3 years ago

Which of the following represents a function?

zhuklara [117]

The fourth one since it will pass the vertical test.

3 0

3 years ago

Jenny opened a package of screws quickly and many of them spilled on the floor. She needs to organize the fasteners according to

hichkok12 [17]

We have to compare diameters and arrange them in order smallest to greatest

We can see units for option A and B are in square inches so they represents area. So first we will find diameter from area using formula

$A = \pi r^{2}$

so for choice (A) area is given as $4.375 \times 10^{7}$ . So plug this in A place in formula and then solve for radius r

$4.375 \times 10^{7} = \pi r^{2}$

$\frac{4.375 \times 10^{7}}{\pi} = \frac{\pi r^{2}}{\pi}$

$1.393 \times 10^{7} } = r^{2}$

$\sqrt{1.393 \times 10^{7}} = \sqrt{r^{2}}$

3731.76 = r

So screw A will have
$diameter = 2 \times r = 2 \times 3731.76 = 7463.52$ inches

Similarly for choice (E) area is $1.428 \times 10^{1} = 14.28$
so again plug in formula

$A = \pi r^{2}$

$14.28 = \pi r^{2}$

$\frac{14.28}{\pi} = \frac{\pi r^{2}}{\pi}$

$4.5477 = r^{2}$

$\sqrt{4.5477} = \sqrt{r^{2}}$

2.13201 = r

So screw E will have
$diameter = 2 \times r = 2 \times 2.13201 = 4.26402$ inches

So diameters of all screws are as follows:

Screw A: 7463.52 inches
Screw B: 1.5 inches
Screw C: $1\frac{7}{8} = \frac{1\times 8+7}{8} = \frac{15}{8} = 1.875$ inches
Screw D: 0.25 inches
Screw E: 4.26402 inches

Comparing all numbers 7463.52, 1.5, 1.875, 0.25, 4.26402 we can see that smallest number is 0.25, then comes 1.5, then 1.875 and then 4.26402 and then 7463.52

So order from least to greatest will be screw D (0.25), B(1.5), C(1.875), E (4.26402), A (7463.52).

So thats the order D,B,C,E,A and the final answer