They mowed total of 11/15 (5/15 + 2/5) already, so they still have 4/15.
Answer:
12
Step-by-step explanation:
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Answer:
x = 7, y = 30 and x = 3, y = 10
Step-by-step explanation:
5x - y = 5, then y = 5x - 5
2y - x^2 = 11
2(5x - 5) - x^2 = 11
10x - 10 - x^2 = 11
-x^2 + 10x -10 = 11
-x^2 + 10x -21 = 0
x^2 - 10x + 21 = 0
(x - 7)(x - 3) = 0
x = 7, y = 30
x = 3, y = 10
Answer:
D No, the integer with the larger absolute value always determines the sign of the sum.
Step-by-step explanation:
Suppose the integer you start with is +3. Adding -1 or -2 or -3 to that will result in 2, 1, or 0, none of which are negative. Only when you add a negative number with an absolute value greater than 3 will you get a sum that is negative. That is, <em>the number in the sum that has the largest absolute value determines the sign of the result</em>. (This is most important when the signs differ, but it is also true when the signs are the same.)
There is no restriction upon x for that function therefore the domain is all real numbers. x=(-oo, +oo)