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3 years ago

I know I just asked a question but I really don’t understand it that much!

Mathematics

2 answers:

Vilka [71]3 years ago

6 0

Answer:

$18.10/ $72.40 * 100

=25%

Step-by-step explanation:

Levart [38]3 years ago

5 0

Answer:

25%

Step-by-step explanation:

18.1x4=72.4

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2. Find the measure of each numbered angle

miskamm [114]

2) 4 = 90
5 = 45
6 = 45

16) this one's a bit long :)

PLEASE READ
I MADE A DUMB MISTAKE WHEN WORKING OUT THE HEIGHT
ITS NOT 8.41 ITS 9
SORRY ABOUT THAT

3 0

4 years ago

Read 2 more answers

EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =

geniusboy [140]

The Lagrangian,

$L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)$

has critical points where its partial derivatives vanish:

$L_x=1-\lambda-2\mu x=0$

$L_y=2+\lambda-2\mu y=0$

$L_z=9-\lambda=0$

$L_\lambda=x-y+z-1=0$

$L_\mu=x^2+y^2-1=0$

$L_z=0$ tells us $\lambda=9$ , so that

$L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu$

$L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}$

Then with $L_\mu=0$ , we get

$x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2$

and $L_\lambda=0$ tells us

$x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}$

Then there are two critical points, $\left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right)$ . The critical point with the negative $x$ -coordinates gives the maximum value, $9+\sqrt{185}$ .