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Dovator [93]
3 years ago
12

HELP ASAP how do I solve this problem

Mathematics
1 answer:
puteri [66]3 years ago
8 0
Answer:

C. 5/3 (5 sqrt 3) (8.66...)

Explanation:

You would use the SohCahToa to find out side x.

First, label your sides (10 is hypotenuse, x is the opposite, and blank side is the adjacent).

Second, figure out which part you have to use (Sin, Cosine, or Tangent). A good way to tell is of you have the missing side on top of the fraction, makes things easier.

Third, once you figure that out then plug stuff in...

Sin(theta) = O/H
Sin(60) = X/10
10sin(60) = X
8.66... = X
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Which expression is equivalent to 10x2y 25x2? 5x2(2y 5) 5x2y(5 20y) 10xy(x 15y) 10x2(y 25)
grin007 [14]

GCF is the highest value that can divide an expression. The equivalent expression to  10x^2y + 25x^2 is 5x^2 (2y + 5)

<h3>Factoring polynomial expressions</h3>

GCF is the highest value that can divide an expression. Given the expression below

10x^2y + 25x^2


Find the factor of each

10x^2y = 5 * 2 * x^2 * y

25x^2 = 5 * 5 * x^2

Since 5x^2 is common to both factors, hence

10x^2y + 25x^2 = 5x^2 (2y + 5)

The equivalent expression to  10x^2y + 25x^2 is 5x^2 (2y + 5)

Learn more on factoring here: brainly.com/question/24734894

5 0
2 years ago
A jar contains 6 red marbles numbered 1 to 6 and 4 blue marbles numbered 1 to 4. A marble is drawn at random from the jar. Find
svetoff [14.1K]

Answer:

Step-by-step explanation:

A

The marble is red. There are 6 red marbles out of ten. So the answer is

6/10 = 0.60

B

Red: 1 3 5

Blue: 1 3

So there are 5 ways that you can draw an odd number. The problem is that they are not evenly distributed.

Red: 1/2 * 3/6 = 1/4 = 0.25

Blue: 1/2 * 2/4 = 0.25

Red + blue = 1/4 + 1/4 = 1/2

You could have gotten 1/2 by taking 5/10 but that won't always work.

C

4 0
3 years ago
The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q
Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

\frac{\sum f}{4}=\frac{100}{4}=25

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF)_{p} = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

     =34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75

The value of first quartile is 34.75.

Q₃ is at the position:

\frac{3\sum f}{4}=\frac{3\times100}{4}=75

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF)_{p} = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

     =44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83

The value of third quartile is 44.83.

Then the inter-quartile range is:

IQR = Q_{3}-Q_{1}

        =44.83-34.75\\=10.08

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}

                                 =\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89

Thus, the probability that a student scored at most 50 on the examination is 0.89.

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3 years ago
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For the years 0 through 24 the profit is either zero or a positive number, so the shop is not in debt for those years.

Answer: A. [0, 24]
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3 years ago
What is half of 1? Its from your bellybottom to your head.
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Half of 1 is 1/2 or 0.5
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