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melisa1 [442]
3 years ago
13

Evaluate without calculator

Mathematics
1 answer:
Vsevolod [243]3 years ago
6 0
-476/375 you just have to multiply neither is divisible by the same number so that’s your final answer
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What is a part of a line , has one endpoint ,continues in one direccion. Math homework
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A ray is a line has one endpoint and a line that goes on forever.
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3 years ago
How do I do this -9 - 16m = 7? What are the steps?
nordsb [41]

m = -1

Step-by-step explanation:

-16m = 7 + 9

-16m = 16

m = 16 ÷ -16

m = -1

4 0
3 years ago
What is the radian measure for an angle that measures 720 degrees?
Scrat [10]

Answer:

720 degrees =  \frac{\pi}{4}\ radians or 0.785 radians.

Step-by-step explanation:

Given:

The angle in degrees in given as 720°

We need to convert this to radians.

Now, we know that, the relation between degrees and radians is given as:

180 degree = π radians

Therefore, using unitary method, the value of 1 degree can be calculated.

∴ 1 degree = \frac{\pi}{180}\ radians

Now, the value of 720 degrees can be calculated by multiplying the unit value and 720. So,

720\ degrees=\frac{\pi}{180}\times 720\ radians\\\\ 720\ degrees =\frac{720\pi}{180}\\\\720\ degrees =\frac{\pi}{4}\ radians=0.785\ radians

Hence, the measure of 720 degrees in radians is \frac{\pi}{4}\ radians or 0.25π radians or 0.785 radians.

6 0
3 years ago
Read 2 more answers
A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears
marta [7]

Answer:

(a) The probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b) <em>n</em> = 28.09

Step-by-step explanation:

The random variable <em>Y</em>ₙ is defined as the total numbers of dollars paid in <em>n</em> years.

It is provided that <em>Y</em>ₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of <em>Y</em>ₙ are:

\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}

(a)

For <em>n</em> = 20 the mean and standard deviation of <em>Y</em>₂₀ are:

\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\

Compute the probability that <em>Y</em>₂₀ exceeds 1000 as follows:

P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z>  4.47)\\=1-P(Z

**Use a <em>z </em>table for probability.

Thus, the probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b)

It is provided that P (<em>Y</em>ₙ > 1000) > 0.99.

P(Y_{n}>1000)=0.99\\1-P(Y_{n}

The value of <em>z</em> for which P (Z < z) = 0.01 is 2.33.

Compute the value of <em>n</em> as follows:

z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n}  \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0

The last equation is a quadratic equation.

The roots of a quadratic equation are:

n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}

a = 16

b = -805.4289

c = 10000

On solving the last equation the value of <em>n</em> = 28.09.

8 0
3 years ago
What are some uses for the distance formula?
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To find the area of a building.
and to make a small farm

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