Look at the 119. Would you say this is closer to 200 or 100? The answer is 22100. You just have to isolate what you are really looking at.
Hello!
I believe it would be 4a(8+3)6
By finding the GCF, 4a, we factor what it can go into. The other factors, 3 and 2, are multiplied and put at the end.
Hope this helps!
Answer:
Step-by-step explanation:
90-39=51
X + y = 7
xy = -30
x + y = 7
x - x + y = -x + 7
y = -x + 7
xy = -30
x(-x + 7) = -30
x(-x) + x(7) = 30
-x² + 7x = -30
-x² + 7x + 30 = 0
-1(x²) - 1(-7x) - 1(-30) = 0
-1(x² - 7x - 30) = 0
-1 -1
x² - 7x - 30 = 0
x² - 10x + 3x - 30 = 0
x(x) - x(10) + 3(x) - 3(10) = 0
x(x - 10) + 3(x - 10) = 0
(x + 3)(x - 10) = 0
x + 3 = 0 or x - 10 = 0
- 3 - 3 + 10 + 10
x = -3 or x = 10
x + y = 7 or x + y = 7
-3 + y = 7 or 10 + y = 7
+ 3 + 3 - 10 - 10
y = 10 or y = -3
(x, y) = (-3, 10) or (x, y) = (10, -3)
The two numbers that add up to 7 and multiply to 30 are -3 and 10.
<h2>Answer- <u>
<em>3</em><em>3</em><em>9</em><em>1</em><em>.</em><em>2</em><em>mi</em><em>le</em></u></h2>
Step-by-step explanation:
Greetings !
Firstly, recall distance-speed equation
Given values:-
- speed(v)=15.7mile/hr
- time(t)=9days
required values:-
solution /work-out
But, first change the time from day to hour
Thus, 9days=216hours
plug in the given values and solve for the distance.
Hope it helps!
