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Diano4ka-milaya [45]
3 years ago
11

Which is a quadratic function

Mathematics
1 answer:
vfiekz [6]3 years ago
4 0

According to Google:

In algebra, a quadratic function, a quadratic polynomial, a polynomial of degree 2, or simply a quadratic, is a polynomial function in one or more variables in which the highest-degree term is of the second degree.

If this is a homework question, just paraphrase!

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The body weight of a healthy 3 month-old colt should be about μ = 60 kg. (Source: The Merck Veterinary Manual, a standard refere
tatuchka [14]

Answer:

a

  The null hypothesis will be  H_o : \mu = 60 \ kg

b

  The alternative hypothesis will be  H_a : \mu <  60

c

  The alternative hypothesis will be  H_a : \mu >  60

d

  The alternative hypothesis will be  H_a : \mu \ne   60

e

  left; right; both

Step-by-step explanation:

Considering question a

    The body weight of the colt is  \mu = 60 \ kg

    The null hypothesis will be  H_o : \mu = 60 \ kg

Considering question b

    Given that we want to test the claim that the average weight of a wild Nevada colt is less than 60 kg , then

The alternative hypothesis will be  H_a : \mu <  60

Considering question c

       Given that we want to test the claim that the average weight of such a wild colt is greater than 60 kg , then

The alternative hypothesis will be  H_a : \mu >  60

Considering question d

   Given that we want to test the claim that the average weight of such a wild colt is different from 60 kg , then

The alternative hypothesis will be  H_a : \mu \ne   60

Considering question e

   For question b  , the corresponding p-value will be on the left because the average weight is less than 60 kg

   For question c  , the corresponding p-value will be on the right  because the average weight is more than 60 kg

   For question d  , the corresponding p-value will be on both  because the average weight is different from  60 kg

5 0
2 years ago
Simplify: sec(θ) sin(θ) cot(θ)
krek1111 [17]

We have to simplify

sec(θ) sin(θ) cot(θ)

Now first of all let's simplify these separately , using reciprocal identities.

Sec(θ) = 1/cos(θ)

Sin(θ) is already simplified

Cot(θ)= cos(θ) / sin(θ) ,

Let's plug these values in the expression

sec(θ) sin(θ) cot(θ)

= ( 1/cos(θ) ) * ( sin(θ) ) * ( cos(θ) / sin(θ) )

= ( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )

sin cancels out with sin and cos cancels out with cos

So , answer comes out to be

=( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )

= 1

4 0
3 years ago
Read 2 more answers
Estimate of 0.75 divided by 3.15
Ganezh [65]
0.3333333333333333333
4 0
3 years ago
a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu
Hunter-Best [27]
What you need to look for is \frac { dr }{ dt } when r=8.

Now:

Volume\quad of\quad a\quad sphere:\\ \\ V=\frac { 4 }{ 3 } \pi { r }^{ 3 }

\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr }  } =\frac { 1 }{ 4\pi { r }^{ 2 } }

And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi  }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }

\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi  }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi  }{ \pi  } \cdot \frac { 1 }{ { r }^{ 2 } }

\\ \\ =-\frac { 64 }{ 3{ r }^{ 2 } } \\ \\ When\quad r=8,\\ \\ \frac { dr }{ dt } =-\frac { 64 }{ 3\cdot { 8 }^{ 2 } } =-\frac { 1 }{ 3 } \\ \\ Answer:\quad -\frac { 1 }{ 3 } \quad cm/sec
3 0
3 years ago
If Greg can do a job in 6 hours, and pepper can do that same job in 5 hours, how long will it take to complete the job if they w
Kay [80]

5 hours and 30 minutes ya que ambos trabajaran la mitad del trabajo

8 0
2 years ago
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