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3 years ago

Which is a quadratic function

Mathematics

1 answer:

vfiekz [6]3 years ago

4 0

According to Google:

In algebra, a quadratic function, a quadratic polynomial, a polynomial of degree 2, or simply a quadratic, is a polynomial function in one or more variables in which the highest-degree term is of the second degree.

If this is a homework question, just paraphrase!

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Select the correct answer.

Fudgin [204]

A) an answer that cannot be written as a fraction.

6 0

3 years ago

If the world population in 2010 is 6.7 million and the rate of growth is by 1.19 percent per year, what will the estimated world

Dennis_Churaev [7]

Answer:

I believe the world population should be 6,700,000,000

Ending Population = Beginning Population * (1 + rate)^years

Ending Population = 6,700,000,000 * (1.19)^40

Ending Population = 7,046,172,293,951

or rounded about 7,046,000,000

(About 7.046 billion)

Step-by-step explanation:

8 0

3 years ago

In triangle ABC, the measure of angle B is 50 degrees. Give possible values for the measures of angles A and C if ABC is a right

Rasek [7]

9514 1404 393

Answer:

A = 90°, C = 40°
A = 40°, C = 90°

Step-by-step explanation:

In a right triangle one angle is 90° and the other angle is the complement of the acute angle given.

Angles A and C are not specified, but we know the other two angles are 40° and 90°. The values can be assigned two ways:

A = 90°, C = 40°

A = 40°, C = 90°

5 0

3 years ago

What is 3/4 * 3/4 * 3/4

Leno4ka [110]

Answer:

0.421875

Step-by-step explanation:

3/4 = 0.75

0.75 * 0.75 * 0.75 = 0.421875

4 0

3 years ago

Read 2 more answers

A line segment AB has the coordinates A (2,3) AND B ( 8,11) answer the following questions (1) What is the slope of AB? (2) What

GalinKa [24]

Answer:

(1) The slope of the line segment AB is 1. $\bar 3$

(2) The length of the line segment AB is 10

(3) The coordinates of the midpoint of AB is (5, 7)

(4) The slope of a line perpendicular to the line AB is-0.75

Step-by-step explanation:

The coordinates of the line segment AB are;

A(2, 3) and B(8, 11)

(1) The slope of a line segment is given by the following equation;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Where;

(x₁, y₁) and (x₂, y₂) are two points on the line segment

Therefore;

The slope, m, of the line segment AB is given as follows;

A(2, 3) = (x₁, y₁) and B(8, 11) = (x₂, y₂)

$Slope, \, m_{AB} =\dfrac{11-3}{8-2} = \dfrac{8}{6} = 1 \frac{1}{3} = 1.\bar3$

The slope of the line segment AB = 1. $\bar 3$

(2) The length, l, of the line segment AB is given by the following equation;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Therefore, we have;

$l_{AB} = \sqrt{\left (11-3 \right )^{2}+\left (8-2 \right )^{2}} = \sqrt{64 +36} = 10$

The length of the line segment AB is 10

(3) The coordinates of the midpoint of AB is given as follows;

$Midpoint, M = \left (\dfrac{x_1 + x_2}{2} , \ \dfrac{y_1 + y_2}{2} \right )$

Therefore;

$Midpoint, M_{AB} = \left (\dfrac{2 + 8}{2} , \ \dfrac{3 + 11}{2} \right ) = (5, \ 7)$

The coordinates of the midpoint of AB is (5, 7)

(4) The relationship between the slope, m₁, of a line AB perpendicular to another line DE with slope m₂, is given as follows;

$m_1 = -\dfrac{1}{m_2}$

Therefore, the slope, m₁, of the line perpendicular to the line AB, that has a slope m₂ = 4/3 = 1. $\bar 3$ is given as follows;

$m_1 = -\left (\dfrac{1}{\frac{4}{3} } \right ) = -\dfrac{3}{4} = -0.75$

The slope, m₁, of the line perpendicular to the line AB is m₁ = -0.75.

8 0

3 years ago