Answer:
9 , -9, -15, -21
Step-by-step explanation:
6-3x-1=-9
6-3x1=9
6-3x3=-15
6-3x5=-21
Part (a):
We will assume that the total amount is Jan's saving account is "m"
Now, "withdrawal" means that she took money from her account, which means that the amount of money in her account decreased by the amount she withdrew.
Sum of negative integers to show her withdrawals = -25$ - 45$ - 75$
Amount of money remaining in her account = m - 145$
The amount of money Jan withdrew = 25$ + 45$ + 75$ = 145$
Part (b):
We will assume that the total amount is Lola's saving account is "n"
Now, "withdrawal" means that she took money from her account, which means that the amount of money in her account decreased by the amount she withdrew.
Sum of negative integers to show her withdrawals = -35$ - 55$ - 65$
Amount of money remaining in her account = n - 155$
The amount of money Lola withdrew = 35$ + 55$ + 65$ = 155$
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
Answer:
f(x)= 3, g(x)=8
Step-by-step explanation:
if you plug 3 into the equation 2x-3, you have 6-3, which is 3.
If you plug 3 into the equation 3x-1, you have 9-1, which is 8
Answer:
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