2 years ago

How do i solve this? and what’s the answer?

Mathematics

1 answer:

Vika [28.1K]2 years ago

6 0

Im pretty sure x y should be 30, I hope this helps.

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chef leo will use a total of 6 1/4 cups of sugar to make 3 chocolate cakes. if each cake recipe requires the same amount of suga

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a. because to divide 6 1/4 and 3 you need to make the improper fraction a mixed number so the equation is 25/4 / 3/1 then you get the recipricol of 3 witch is 1/3 then you multiply 1/3 x 25/4 whitch is 25/12=2 1/12

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3 years ago

West middle school ordered 121 boxes of markers. If there are 22 teachers how many boxes does each teacher get? Write answer as

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The answer should be 5.5 because you have to divide it. The fraction would be 5 over 10

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3 years ago

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BaLLatris [955]

Answer

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2(9)

B) 2(10+2)

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3 years ago

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3 years ago

Find the first term and the common ratio <br>third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$

So, Common Ratio r = 2

Finding First term using eq(1)

$a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}$

So, First term a₁ = 3/2 and common ratio r = 2

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2 years ago