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blsea [12.9K]
3 years ago
12

-3÷(-2/5) simplify the expression

Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0

Answer:

7.5 is the answer you are looking for

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Si una persona aprovecha un descuento del 20% y paga 60.000 pesos por una camisa,¿Cuál era el precio de la camisa sin el descuen
oksano4ka [1.4K]

Answer:

the price of the shirt without discount is 75,000 pesos

Step-by-step explanation:

The computation of the price of the shirt without discount as follows:

There is a discount of 20%

And the person pays 60,000 pesos after considering the discount

So, the price without discount is

= 60,000 pesos ÷ 0.80

= 75,000 pesos

hence, the price of the shirt without discount is 75,000 pesos

6 0
3 years ago
The set S consists of all odd multiples of 3: S = {..., -9, -3, 3, 9,...}. If the integers x and y are in S, then which of the f
tankabanditka [31]
I think it is gonna be xy

because if ur set contains all odd multiples of 3 (-9,-3,3,9,15,21,27...
and u pick any 2 of those numbers and multiply them u will end up with an odd numbered multiple of 3

and if u pick out any 2 numbers in ur set..and do any of the other things in ur answer choices, it will not always be an odd numbered multiple of 3
4 0
3 years ago
Can someone please help me??????????
madam [21]
I hoped this help c 0.43
4 0
3 years ago
81
Rasek [7]

Answer:

2.6

Step-by-step explanation:

7 0
3 years ago
Given: cos θ=-4/5, sin x = -12/13, θ is in the third quadrant, 
USPshnik [31]

By definition of tangent,

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

Recall the double angle identities:

sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)

cos(2<em>θ</em>) = cos²(<em>θ</em>) - sin²(<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

where the latter equality follows from the Pythagorean identity, cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1. From this identity we can solve for the unknown value of sin(<em>θ</em>):

sin(<em>θ</em>) = ± √(1 - cos²(<em>θ</em>))

and the sign of sin(<em>θ</em>) is determined by the quadrant in which the angle terminates.

<em />

We're given that <em>θ</em> belongs to the third quadrant, for which both sin(<em>θ</em>) and cos(<em>θ</em>) are negative. So if cos(<em>θ</em>) = -4/5, we get

sin(<em>θ</em>) = - √(1 - (-4/5)²) = -3/5

Then

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

tan(2<em>θ</em>) = (2 sin(<em>θ</em>) cos(<em>θ</em>)) / (2 cos²(<em>θ</em>) - 1)

tan(2<em>θ</em>) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

tan(2<em>θ</em>) = 24/7

4 0
3 years ago
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