Identify the type of arc.
1 answer:
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Answer:
f(x) = |x|
g(x) = |x| - 2
h(x) = |x| + 3
Step-by-step explanation:
All the functions graphed represent the absolute value functions.
Since function g(x) passes through (0, 0) and (1, 1),
Let the equation of a line passing through these points is,
y = mx + b
Slope of the line passing through these points 'm' =
m = 1
y-intercept of the line 'b' = 0
Therefore, equation of the line will be,
y = x
And the function representing the two lines (both are the mirror images) joining at the origin will be,
f(x) = |x|
When the parent function is shifted 3 units up, the new function will be
h(x) = |x| + 3
When the parent function is shifted 2 units down,
g(x) = |x| - 2