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3 years ago

Jasmin can walk 1/4 mile every 1/5 hour. At this rate, how far can Jasmin walk in one hour?

Mathematics

2 answers:

SSSSS [86.1K]3 years ago

7 0

Answer:

Jazmeen can walk 1.25 miles in one hour.

Step-by-step explanation:

Hope this helps!

Have a great day! :)

Dvinal [7]3 years ago

4 0

Answer:

hope this helps :)

Step-by-step explanation:

Since we know how far she can walk in 1/5 (one fifth) of an hour, if we multiply this distance by 5, we will find out how far she can walking in 5/5 (five fifths) of an hour, or to be clear: in one hour.

So, 5 x 1/4 miles = 5/4 or 1.25 miles per hour

Jazmeen can walk 1.25 miles in one hour.

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Factor the trinomial step by step & explain 2x^2+ 5x + 3

Colt1911 [192]

Answer:

One way to factor equation is to find the zeros. Its obvious that x=-1 is solution for this. So one factor is (x+1)

the next factor should include 2x at first (because we have 2x^2 in the equation which can not be made any other way)

Let's suppose the factor is (x+1)(2x+b)

Since we do not know what is b open the brackets 2x^2+bx+2x+b. If this is equal to 2x^2+5x+3 then b=3. We are left with (x+1)(2x+3)=2(x+1)(x+3/2)

Would go for other shorter solutions, but they require some deeper understanding like Horner's scheme,Fermat's Theorem or even deeper which I assume You will not understand)

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3 years ago

How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%

blondinia [14]

The trick is to exploit the difference of squares formula,

$a^2-b^2=(a-b)(a+b)$

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

$(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2$

Whatever you do to the denominator, you have to do to the numerator too. So

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2$

Expand the numerator:

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}$

So we have

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2$

But √12 = √(3•4) = 2√3, so

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}$

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3 years ago

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Vitek1552 [10]

Mr. Vella can build the wall in 4 days, however only works on it for 3 days. That means that he has completed 75% of the and is leaving 25% for his apprentice.

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It took the apprentice 1.5 days to finish the wall.

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