Answer:
Not sure how answer that bc I can't really see it that well but I hope that you get your answer!!
The formula that is useful for solving both of these problems is ...

9. Given v₁=15, a=9.8, d=10, find v₂.
... (v₂)² = 15² + 2·9.8·10
... v₂ = √421 ≈ 20.5 . . . . m/s
10. Given d=12 m when a=-9.8 m/s² and v₂=0, find d when a=0.17·(-9.8 m/s²).
The formula tells us that d=(v₁)²/(2a), which is to say that the distance is inversely proportional to the acceleration. If acceleration is 0.17 times that on earth, distance will be 1/0.17 ≈ 5.88 times that on earth.
(12 m)/0.17 ≈ 70.6 m
Answer:
Test scores of 10.2 or lower are significantly low.
Test scores of 31 or higher are significantly high
Step-by-step explanation:
Z-score:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Significantly low:
Z-scores of -2 or lower
So scores of X when Z = -2 or lower




Test scores of 10.2 or lower are significantly low.
Significantly high:
Z-scores of 2 or higher
So scores of X when Z = 2 or higher




Test scores of 31 or higher are significantly high
Answer:

Step-by-step explanation:
<u>Formula for area of rectangle:</u>
= length × width
<u>Area of the smaller rectangle:</u>
length = 7
width = 6
= 7 × 6
= 42
<u>Area of the larger rectangle:</u>
length = 7 + 4 = 11
width = 6 + 2 = 8
= 11 × 8
= 88
<u>Area of the shaded region:</u>
= Area of the larger rectangle - Area of the smaller rectangle
= 88 - 42
= 46
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>