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densk [106]
3 years ago
14

Elam can wire a light in 40

Mathematics
2 answers:
NeX [460]3 years ago
6 0

Answer:

24 minutes

Step-by-step explanation:

We use 1/a + 1/b = 1/c

where a and b are the individual times and c is the time together

1/40 + 1/60 = 1/c

Multiply each side by 120c

120c( 1/40 + 1/60 = 1/c)

3c + 2c = 120

5c = 120

Divide each side by 5

5c/5 = 120/5

c = 24

zvonat [6]3 years ago
5 0

Answer: 24 minutes

Step-by-step explanation: To solve this kind of a problem which is called a work problem, it's important to understand the following idea.

Since Elam can wire a light in 40 minutes, we know that in 1 minute,

Elam can wire 1/40 of the light and in 2 minutes, Elam can wire 2/40 of it.

Therefore, in <em>t</em> hours, Elam can wire t/40 of the light.

The same applies for Michael, in <em>t</em> hours, he can wire t/60 of the light.

So to solve the problem, we use the following formula:

Part of job done by Elam + part of job done Michael = 1 job done

The part of the job done by Elam is t/40 and t/60 for Michael.

So we have t/40 + t/60 = 1.

Now multiply both sides by 120 to get 3t + 2t = 120

or 5t = 120 so t = 24.

So it takes 24 minutes if they work together.

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What number is 300% of six
nadya68 [22]

Answer:

18

Step-by-step explanation:

100% of 6 is 6 so 300% (which does not actually exist) would be 3 times as much. 6x3=18

6 0
3 years ago
Read 2 more answers
Pls help math problem pls
Dovator [93]

Answer: The fourth choice

Step-by-step explanation:

(f - g)(x) = f(x) - g(x) = 4x^{2} - 5x - (3x^{2} + 6x - 4) = x^{2} - 11x + 4

5 0
2 years ago
The radius of a sphere is 1/3 ft what is the approximate volume of the sphere
Katen [24]

Answer:

0.16 ft

Step-by-step explanation:

v = 4/3 πr³

v = 4/3 × 3.142 × 1/3 × 1/3 × 1/3

v = 0.16 ft

7 0
2 years ago
Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confide
ioda

Answer:

The question is incomplete, but the step-by-step procedures are given to solve the question.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{\sigma}{\sqrt{n}}

The lower end of the interval is the sample mean subtracted by M.

The upper end of the interval is the sample mean added to M.

The 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (lower end, upper end).

7 0
3 years ago
Four friends go to an amusement arcade.
galben [10]

<u><em>Answer:</em></u>

<u>The rule is: </u>

T(x) = 8x + 20

<em><u>Explanation:</u></em>

<u>We are given that:</u>

<u>The rule for the amount that one friend pays is:</u>

C(x) = 2x + 5

<u>Now, we know that:</u>

Each of the four friends will pay the entry fee which is $5 per person

The 4 friends will play the same number of games represented by x

<u>This means that:</u>

We can simply get the rule for the total amount to be paid by the four friends (T(x)) by multiplying the amount paid by each friend by 4

<u>This means that:</u>

T(x) = 4 * C(x)

T(x) = 4(2x + 5)

T(x) = 8x + 20

Hope this helps :)

4 0
3 years ago
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