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densk [106]
3 years ago
14

Elam can wire a light in 40

Mathematics
2 answers:
NeX [460]3 years ago
6 0

Answer:

24 minutes

Step-by-step explanation:

We use 1/a + 1/b = 1/c

where a and b are the individual times and c is the time together

1/40 + 1/60 = 1/c

Multiply each side by 120c

120c( 1/40 + 1/60 = 1/c)

3c + 2c = 120

5c = 120

Divide each side by 5

5c/5 = 120/5

c = 24

zvonat [6]3 years ago
5 0

Answer: 24 minutes

Step-by-step explanation: To solve this kind of a problem which is called a work problem, it's important to understand the following idea.

Since Elam can wire a light in 40 minutes, we know that in 1 minute,

Elam can wire 1/40 of the light and in 2 minutes, Elam can wire 2/40 of it.

Therefore, in <em>t</em> hours, Elam can wire t/40 of the light.

The same applies for Michael, in <em>t</em> hours, he can wire t/60 of the light.

So to solve the problem, we use the following formula:

Part of job done by Elam + part of job done Michael = 1 job done

The part of the job done by Elam is t/40 and t/60 for Michael.

So we have t/40 + t/60 = 1.

Now multiply both sides by 120 to get 3t + 2t = 120

or 5t = 120 so t = 24.

So it takes 24 minutes if they work together.

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The bottom shape is a square prism with base edges of 3 cm and a height of 10 cm. What is the volume of the composite figure if
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Add 90 and 6 to get 96.
6 0
3 years ago
Clare is paid $90 for 5 hours of work. At thos rate how many seconds does i take for her to earn 25 cents?
natka813 [3]

We are given

Clare is paid $90 for 5 hours of work

Total money paid =$90

total hours of work =5 hours

so, firstly  we will find rate of work

rate of work = ( total money paid)/( total hours of work)

now, we can plug values

and we get

The rate of work is

=\frac{90}{5}

=18 $/ hour

now, we have to find time for amount paid is 25 cents

so, amount paid =25 cents

100 cents =1$

so, amount paid =$ 0.25

Since, the rate is constant

so, we can take same rate here

now, we can use formula

rate of work = ( total money paid)/( total hours of work)

now, we can plug values

18=\frac{0.25}{T}

now, we can solve for T

T=\frac{0.25}{18} hour

since, T is in hours

so, we can change into seconds

1 hour =3600seconds

so, we can plug

T=\frac{0.25}{18}\times 3600 seconds

T=50 seconds......................Answer


6 0
3 years ago
Please help with #6. How do I find all of the real zeros? Thank you!!!
Morgarella [4.7K]

I'm assuming you're referring to problem 6. You are asked to find the number of x intercepts or roots, which is another term for "zero". I prefer the term root or x intercept as "zero" seems misleading. Anyways, all we do is count the number of times the graph crosses the x axis. This happens 4 times as shown in the attached image below. I have marked these points in red. The graph can directly cross over the x axis, or it can touch the x axis and then bounce back. Either way, it is considered an x intercept.

<h3>Answer: there are 4 x intercepts (or 4 roots)</h3>

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4 years ago
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When you finally retire, you want to be able to draw from an account an annual salary of $100,000 for 20 years. Approximately ho
tankabanditka [31]
PV = P(1 - (1 + r)^-n) / r; where P is the periodic withdrawal = $100,000; r = rate = 5% = 0.05; n = number of periods = 20 years.

PV = 100000(1 - (1 + 0.05)^-20) / 0.05 = 100000(1 - 1.05^-20) / 0.05 = 100000(1 - 0.3769) / 0.05 = 100000(0.6231) / 0.05 = 100000(12.4622) = 1,246,221 ≈ $1,250,000
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3 years ago
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