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densk [106]
3 years ago
14

Elam can wire a light in 40

Mathematics
2 answers:
NeX [460]3 years ago
6 0

Answer:

24 minutes

Step-by-step explanation:

We use 1/a + 1/b = 1/c

where a and b are the individual times and c is the time together

1/40 + 1/60 = 1/c

Multiply each side by 120c

120c( 1/40 + 1/60 = 1/c)

3c + 2c = 120

5c = 120

Divide each side by 5

5c/5 = 120/5

c = 24

zvonat [6]3 years ago
5 0

Answer: 24 minutes

Step-by-step explanation: To solve this kind of a problem which is called a work problem, it's important to understand the following idea.

Since Elam can wire a light in 40 minutes, we know that in 1 minute,

Elam can wire 1/40 of the light and in 2 minutes, Elam can wire 2/40 of it.

Therefore, in <em>t</em> hours, Elam can wire t/40 of the light.

The same applies for Michael, in <em>t</em> hours, he can wire t/60 of the light.

So to solve the problem, we use the following formula:

Part of job done by Elam + part of job done Michael = 1 job done

The part of the job done by Elam is t/40 and t/60 for Michael.

So we have t/40 + t/60 = 1.

Now multiply both sides by 120 to get 3t + 2t = 120

or 5t = 120 so t = 24.

So it takes 24 minutes if they work together.

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Using the data in the table, use the exponential smoothing method with alpha=0.5 and a February forecast of 500 to forecast
Sever21 [200]

Answer:

Step-by-step explanation:

The formula to calculate the forecast could be determine by using the exponential smoothing method :

Ft = F(t-1) +  \alpha [A(t-1) - F(t-1)]

Where ,Ft is the Forecast for period t

F(t-1) is the Forecast for the period previous to t

A(t-1) is the Actual demand for the period previous to t

\alpha = Smoothing constant

To get the forecast for may and june   the above formula with \alpha =0.5 and april forecast of 500 will be used

For march

=500+0.5(520-500)\\\\=500+0.5\times20\\\\=500+10\\\\=510

For April

=510+0.5(535-510)\\\\=510+0.5\times25\\\\=510+12.5\\\\=522.5

For May

=522.5+0.5(550-5225)\\\\=522.5+0.5\times27.5\\\\=522.5+13.75\\\\=536.25

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6 0
4 years ago
what is the equation in slope-intercept form for the line that passes through (3, 7) and is perpendicular to 3x-5x=8
Galina-37 [17]

Answer:

5x + 3y = 36

Step-by-step explanation:

First we need to rewrite 3x-5y=8 in slope-intercept form.

y =  \frac{3}{5} x -  \frac{8}{5}

The slope of this line is

\frac{3}{5}

The line perpendicular to this line will have a slope that is the negative reciprocal of 3/5, which is

m =  -  \frac{5}{3}

This line passes through (3,7).

The equation is given by:

y-y_1=m(x-x_1)

We substitute the point and slope to get:

y - 7 =  -  \frac{5}{3} (x - 3)

We multiply through by 3 to get:

3y - 21 =  - 5(x - 3)

Expand to obtain:

3y - 21 =  - 5x  + 15

3y  + 5x =  15 + 21

5x + 3y = 36

6 0
3 years ago
On the graph of the equation 5x - y = 8, the point whose y-coordinate is 7 has an x-coordinates of ?
Lemur [1.5K]

Answer:

x = 3

Step-by-step explanation:

To find the x-coordinate, substitute y = 8 into the equation abd solve for x

5x - 7 = 8 ( add 7 to both sides )

5x = 15 ( divide both sides by 5 )

x = 3

Thus (3, 7) is a solution to the equation


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