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2 years ago

What is the solution to the system of equations y=x+4 and y=-4+x

2 answers:

amm18122 years ago

5 0

To solve for the solution of this system of equations,there are many ways to go about doing it, finding the point where the lines both intersect at.

One of the easiest is substitution, so plug in either one of the equations for the other one.

Y = X+4
Y = -4 + X
X+4 = -4 + X

Then solve for the X value to obtain the X coordinate of the point.

X+4 = -4 + X
X - X + 4 + 4 = -4 + 4 + X - X
8 = 0.
Since after trying to solve for X, we couldn't solve for it, and instead gave us numbers that are not equal to each other, there is no solution to these systems of equations, in other words, they don't intersect at a particular point.

zhannawk [14.2K]2 years ago

3 0

X=y - 4 im not all the way sure

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Help due Monday......

pantera1 [17]

Step-by-step explanation:

5) 2.4×10^-5 / 4.5×10^-11

2.4×10^-5= 0.000024
4.5×10^-11= 0.000000000045

=0.000024/0.000000000045

=24/1 × 1,000,000/45

=24,000,000/45

=533,333.33°

=5.33333°×10^5

**NOT SURE ABOUT THIS QUESTION

6) (4,-2)

7) --------

8)

2x + 3 = 5x - 2

2x - 5x = - 2 - 3
-3x = -5
x = -5/-3
x = 1.66°

6x + 4 = 6x + 4

6x - 6x = 4 - 4
0x = 0

2 (2x + 3) = 8x - 2

4x + 6 = 8x - 2
4x - 8x = -2 - 6
-4x = -8
x = -8/-4
x = 2

-3x + 2 = -3x + 5

-3x + 3x = 5 - 2
0x = 3

Letter be has no solution because it is broken down as "0x = 0"

6 0

3 years ago

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$

we know that $cos^2A+sin^2A=1$ , so we have that

$f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)$

$lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19$

So f(0,0)=ln19.

8 0

3 years ago

A company rents water tanks shaped like cylinders. Each tank has a radius of 6 feet and a height of 2 feet. The cost is $3 per c

choli [55]

It should be 36.00 dollars

7 0

3 years ago

-How can you solve compound inequalities in one variable?

Tresset [83]

Answer:

Isolate the variable by subtracting 7 from all 3 parts of the inequality, and then dividing each part by 2. To solve inequalities like a < x < b, use the addition and multiplication properties of inequality to solve the inequality for x.

Hope this was able to help you

5 0

3 years ago

I want the 17 No the answer only the name of the fraction

Valentin [98]

Answer: A. 15

Explanation:

n is equal to 15 because 15 divided by 5 is 3. therefore, 3 = 15/5.

5 0

3 years ago