BABYYYY SOSAAAAA CASH CARTIIII
2.6/1.3 * (10^9/10^2)
2*10^7
Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Answer:
Measure of exterior angle ABD = 136°
Step-by-step explanation:
Given:
measure of ∠A = (2x + 2)°
measure of ∠C = (x + 4)°
measure of ∠B = x°
Find:
Measure of exterior angle ABD
Computation:
Using angles sum property
∠A + ∠B + ∠C = 180°
So,
(2x + 2) + (x + 4) + x = 180
4x + 6 = 180
4x = 176
x = 44
So,
measure of ∠B = x°
measure of ∠B = 44°
Measure of exterior angle ABD = 180 - measure of ∠B
Measure of exterior angle ABD = 180 - 44
Measure of exterior angle ABD = 136°
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