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Damm [24]
1 year ago
9

Your friend has a credit card with an APR of 49.9%. What would his finance charge be on a $500 charge for just 1 month?(round to

the hundredths place)
Mathematics
1 answer:
Anestetic [448]1 year ago
4 0

The finance charge on $500 at 49.9% APR will be $20.79 for one month.

Finance charge = principal × rate

Now monthly charge= P×R×(1/12)

charge = 500 ×0.499 ÷12 = $ 20.79166.. ≈ $20.79

APR is the short hand representation of annual percentage rate which is the rate of interest issued by a bank on a credit card or a loan.

An interest rate is the amount of interest that is payable each period stated as a percentage of the total that was lent, deposited, or borrowed.

The principal amount of the loan , interest rate of the loan , frequency of compounding the interest on the rate, and duration or time of the loan, deposit amount, or borrowing determine the total amount of the interest on the sum that was lent or borrowed.

To learn more about finance charge visit:

brainly.com/question/2588555

#SPJ9

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Answer:

=  - 4 \times 2 + 4 \times ( - 4) + c \\   = - 8  - 16 + c \\  = 24 + c \\  \frac{ - c}{ - 1}  =  \frac{24}{ - 1}  \\ c =  - 24

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Simplify....... <br><br><br><br>-9-6c-j​
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Step-by-step explanation:

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Lanie’s room is in the shape of a parallelogram.
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3 years ago
The mean preparation fee H&amp;R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
What is the solution to this equation 8 - 2x + 6x = 24
san4es73 [151]

x = 4

First you combine like terms:

8 + 4x = 24

Then solve:

4x = 24 - 8

4x = 16

x = 16/4

x = 4

4 0
3 years ago
Read 2 more answers
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