Using elimination method. Using substitution will cause some fraction problems.
c- child tickets
a- adult tickets
4a + 7c = $83
5a + 6c = $90
multiply by -5
-20a - 35c = -$415
20a + 24c = $360
-11c= -$55
c = $5 child tickets
4a + 7(5)= $83
4a + 35 = $83
4a = $48
a= $12 adult tickets
Let u = x², then we would have u² + 5u - 6 = 0
From here, we can factor it and get us (u-1)(u+6) = 0
So our solution for u is u = -6 or 1.
Now substitute u back to x².
x² = -6 or 1
x = ±√(-6) or ±√1
Since ±√(-6) is not real number, we ignore it.
Which leave us x = ±√1 = <span>±1
So our real solution is x = -1 or 1.</span>
This is the answer (4,3) x=4, y=3
You have to do the inverse of divide so multiply to find out a
14x 3= 42
S= 42
