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zmey [24]
3 years ago
10

I NEED HELP WITH B, THE MONTHLY BILL IS THE $15.34

Mathematics
1 answer:
dezoksy [38]3 years ago
6 0
The answer is 9.35 pounds
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(3,4) is an example of a/an
Elan Coil [88]

Answer:

Ordered pair

Definition: An ordered pair is a pair of numbers in parentheses that declare the location of a point on a graph.

4 0
4 years ago
Kayla's father throws Kayla a graduation party that costs $775. He pays the DJ $250, $75 for the cake, and $5 per party guest fo
Charra [1.4K]

Answer:

90 people

Step-by-step explanation:

Total: $775

DJ: $250

Cake: $75

Unknown party guests each getting $5

Let the unknown be x

We can form an equation; <em>DJ + Cake + x number of party guests = $775</em>

<em>250 + 75 + 5x = 775</em>

<em>325 + 5x = 775</em>

Subtract 325 from <u>both sides of the equals sign</u>.

<em>5x = 450</em>

Make <em>x</em> the subject and divide both sides by 5

<em>x = 90</em>

There were 90 party guests.

7 0
4 years ago
A company takes out an insurance policy to cover accidents that occur at its manufacturing plant. The probability that one or mo
yKpoI14uk [10]

Answer:

0.289792.

Step-by-step explanation:

If we define a month with one or more accident as "success"; and

A month with no accident as "failure" .

  • P(one or more accidents will occur during any given month)=0.60.
  • P(no accident will occur during any given month)=1-0.60=0.40

We want to calculate the probability that there will be at least four months in which no accidents occur before the fourth month in which at least one accident occurs.

in this case, let k=number of failures before the fourth success

Therefore, k\geq 4

k follows a negative binomial distribution.

Therefore, the probability is:

P(k\geq 4)=1-P(k\leq 3)\\=1-\sum_{k=0}^{3}\left(\begin{array}{ccc}3+k\\k\end{array}\right)(0.60)^4(0.40)^k\\=1-(0.60)^4 \left[\left(\begin{array}{ccc}3\\0\end{array}\right)(0.40)^0+\left(\begin{array}{ccc}4\\1\end{array}\right)(0.40)^1+\left(\begin{array}{ccc}5\\2\end{array}\right)(0.40)^2+\left(\begin{array}{ccc}6\\3\end{array}\right)(0.40)^3\right]\\=1-(0.60)^4 \left[ 1+1.6+1.6+1.28\right]\\=1-(0.60)^4[5.48]\\=0.289792

The required probability is 0.289792.

4 0
3 years ago
Guysss plsss HEELPPP ME ILL MARK BRAINLIEST PLLLSSSSSS HELP
Vitek1552 [10]

Answer:

y=-2\,(x-6)^2+246

with the video game cost of x = $6

This agrees with the last option in the list of possible answers

Step-by-step explanation:

Recall that the maximum of a parabola resides at its vertex. So let's find the x and y position of that vertex, by using first the fact that the x value of the vertex of a parabola of general form:

y=ax^2+bx+c

is given by:

x_{vertex}=\frac{-b}{2\,a}

In our case, the quadratic expression that generates the parabola is:

y=-2x^2+24x+174

then the x-position of its vertex is:

x_{vertex}=\frac{-b}{2\,a}\\x_{vertex}=\frac{-24}{2\,(-2)}\\x_{vertex}=\frac{-24}{-4)}\\x_{vertex}=6

This is the price of the video game that produces the maximum profit (x = $6). Now let's find the y-position of the vertex using the actual equation for this value of x:

y=-2x^2+24x+174\\y_{vertex}=-2\,(6)^2+24\,(6)+174\\y_{vertex}=-72+144+174\\y_{vertex}=246

This value is the highest weekly profit (y = $246).

Now, recall that we can write the equation of the parabola in what is called "vertex form" using the actual values of the vertex position (x_{vertex},y_{vertex}):

y-y_{vertex}=a\,(x-x_{vertex})^2\\y-246=-2\,(x-6)^2\\y=-2\,(x-6)^2+246

Therefore the answer is:

y=-2\,(x-6)^2+246

with the video game cost of x = $6

6 0
3 years ago
Eddie's salary is $3500 per month. Find the Eddie's earnings per year
Vikki [24]

42,000  if he earns 3500 per month just multiply that times 12 which is the amount of months in a year and you get $42,000

8 0
3 years ago
Read 2 more answers
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