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Musya8 [376]
3 years ago
14

Nevia spent 0.75 on 1.5 pounds of bananas. At, this rate, how much will 6 pounds of bananas cost?

Mathematics
2 answers:
kkurt [141]3 years ago
8 0
It will cost 12 dollars because you divide .75 by 1.5 to find the price per unit then you multiply by 6
Marina CMI [18]3 years ago
6 0

Answer:

3.00

Step-by-step explanation:

6.0 / 1.5 = 4

0.75 * 4 = 3.00

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bixtya [17]
Beaded braclets at 9 beads each Then 156 beads = 156/9 17.333 But the answer is 17 braclets since she cannot make .333 of a braclet
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Let s be the annual sales​ (in millions) for an electronic device. The value of s is 13.9 for 2009. What does sequals13.9 mean i
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S would be the annual sales of the electronic device. In this case, that number is in the millions.

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Or written out, it would be: 13,900,000
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Sonya has 140 beads. how many bags of 10 beads does she need so that she will have 200 beads in all
Vikentia [17]
If Sonya already has 140 beads, she needs 60 beads in order to have a total number of 200 beads. You have to find how many bags (that hold 10 beads) are needed to add up to 60.

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7 0
3 years ago
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4 out of 9 dogs weigh less than 20 pounds. What is the decimal equivalent for the number of dogs weighing under 20 pounds?
iVinArrow [24]

4/9=0.44444444 repeating

6 0
3 years ago
Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo
NikAS [45]

Answer:

[tex]4608\sqrt{3}[/tex]

Step-by-step explanation:

1. \sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}

2. \sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}   <em>factoring 96</em>

<em>since \sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}</em>

3. \sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>using exponent rule - (a^{b}) ^{c} = a^{bc}</em>

<em> \sqrt{2^{5} } = 2^{5/2}</em>

4. 2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>doing some simple simplification and 4=2^{2}  and 6=2*3</em>

5. 2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}

<em>collecting the roots on one side and applying exponent rule</em>

6. \sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}

<em>Applying exponents rule on all \sqrt{3} and \sqrt{2}</em>

<em>7. 2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}</em>

<em>combining all powers of 2</em>

8. 2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}

<em>Simplifying</em>

9. 2^{9} *3^{2}\sqrt{3}

10. 512*9\sqrt{3}

11. 4608\sqrt{3}

3 0
3 years ago
Read 2 more answers
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