Both a rhombus and a rectangle have diagonals that are perpendicular bisectors, but the ones formed in a square are all congruent, so that is probably the most descriptive one.
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Don't you mean "the sum of the squares ..."?
The sum of the squares of two consecutive whole numbers is 25. Find the numbers. Let the first be represented by x and the second by x+1.
Then x^2+(x+1)^2=25. Expanding, x^2+x^2+2x+1=25.
Rewriting this as a quadratic equation in standard form,
2x^2+2x+1=25, or 2x^2+2x-24=0. Simplifying, x^2+x-12=0.
Factoring, (x-3)(x+4)=0. Solving for x: x-3=0, so x=3; x+4=0, so x=-4.
Choose the positive x value: x=3. Then the next consecutive number is 2+1=3+1=4.
Check: Does 3^2 + 4^2 = 5^2 = 25? Yes.
The numbers are 3 and 4.
Answer:
no association
Step-by-step explanation:
hope this helps I'm pretty sure this is right
Answer: Substitute -108 into the place of b
Step-by-step explanation:
-6=b/18
-6=-108/18
-6=-6
You get the same answer, which makes it correct.