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3 years ago

10

PLEASE HELP!!!!

1 answer:

Hatshy [7]3 years ago

8 0

Answer: At time 0, there are 18 gallons of water. That gives you point (0, 18).This point is a dot on 18 on the y-axis. After 2 hour, the water went down 2 gallon. At hour 2, there are now 16 gallons left. This gives you point (1, 16).To plot it, start at the origin, (0, 0), go 2 unit right on the x-axis, and 16 units up on the y-axis, and place a dot there. Now connect the two dots and extend the line down to the right until you intersect the x-axis. You should intersect the x-axis at 10.

Step-by-step explanation:

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belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

$r = \frac{\Delta T_{X}}{\Delta T_{Y}}$

$r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}$

$r = 11\,\frac{^{\circ}X}{^{\circ}Y}$

The difference between current temperature in Y linear scale with respect to freezing point is:

$\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)$

$\Delta T_{Y} = 115\,^{\circ}Y$

The change in X linear scale is:

$\Delta T_{X} = r\cdot \Delta T_{Y}$

$\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)$

$\Delta T_{X} = 1265\,^{\circ}X$

Lastly, the current temperature on the X scale is:

$T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X$

$T_{X} = 1150\,^{\circ}X$

The current temperature on the X scale is 1150 °X.

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Answer: 0.72

Step-by-step explanation:

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Now it would be
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