The answer is 11 and 14/33.
6 and 10 are 2 units away from a positive 8 on the number line
The blue line...
(1,2),(3,1)
slope = (1 - 2) / (3 - 1) = -1/2
there is a y int at (0,2.5) or (0,5/2)
it is shaded below the line....and it is a solid line
this inequality is :
y = -1/2x + 5/2
1/2x + y = 5/2
x + 2y = 5
x + 2y < = 5.....this is ur inequality
red line...
(0,4), (1,1)
slope = (1 - 4) / (1 - 0) = -3/1 = -3
there is a y int at (0,4)
it is shaded below the line...and it is a solid line
this inequality is :
y = -3x + 4
3x + y = 4
3x + y < = 4 ...this is ur inequality
summary :
ur 2 inequalities are :
x + 2y < = 5 and 3x + y < = 4
Answer:
The average value of over the interval is .
Step-by-step explanation:
Let suppose that function is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of over the interval by algebraic handling:
The average value of over the interval is .