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stich3 [128]
3 years ago
8

Jude factored 28x2 as (14x)(2.2).

Mathematics
1 answer:
garri49 [273]3 years ago
4 0

Answer: Yasmin factored 28x2 correctly as (7x)(4x)

Step-by-step explanation:

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The proof that point (1,root 3) lies on the circle that is centered at the origin and contains the point (0,2) is found in the t
AURORKA [14]
<h2>Answer:</h2>

D. Distance formula

<h2>Step-by-step explanation:</h2>

The \ \mathbf{distance} \ d \ between \ the \ \mathbf{points} \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ in \ the \ plane \ is:\\ \\ d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

As in the statement:

<em>The distance form</em> (0,0) to (0,2) is \sqrt{(0-0)^2+(2-0)^2}=\sqrt{2^2}=2 <em>whose justification is the </em><em>Distance Formula. </em>

<em />

Here in this statement the justification is also the Distance Fromula, so we take the distance from (0,0) \ to \ (1,\sqrt{2}) whose result is also 2 and is the radius of the circle.

3 0
3 years ago
Read 2 more answers
Which expression is equivalent to (5x^3)(2x)^3
Elanso [62]

Answer:

\large\boxed{(5x^3)(2x)^3=40x^6}

Step-by-step explanation:

(5x^3)(2x)^3\qquad\text{use}\ (ab)^n=a^nb^n\\\\(5x^3)(2^3x^3)=(5x^3)(8x^3)\qquad\text{use commutative law}\\\\=(5\cdot8)(x^3x^3)\qquad\text{use}\ a^na^m=a^{n+m}\\\\=40x^{3+3}=40x^6

3 0
4 years ago
Read 2 more answers
What is the mode and mean for class A and the range and medium for class B????
melamori03 [73]
Hello!

First you have to list the data in both classes

Class A
41, 42, 45, 46, 47, 48, 52, 53, 54, 59, 61, 61, 64, 68, 71, 82, 85, 90

Class B
41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95
------------------------------------------------------------------------------------------------------
First we are going to find the mode and mean of class A

The mode is the number that appears the most

The number that appears the most is 61

The mode is 61

To find the mean you add all the numbers together and divide the sum by the amount of numbers added

41 + 42 + 45 + 46 + 47 + 48 + 52 + 53 + 54 + 59 + 61 + 61 + 64 + 68 + 71 + 82 + 85 + 90 = 1069

Divide this by the amount of numbers added

1069 / 18 = 59.3888...

The mean is 59.3888

The mode is 61 and the mean is 59.39 for class A
------------------------------------------------------------------------------------------------------
We are going to find the range and median for class B

To find the range you subtract the smallest number from the largest on

The smallest number is 41
The largest number is 95

Subtract these

95 - 41 = 54

The range is 54

To find the median you list the numbers from least to greatest and look for the number in the middle

41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95

The number in the middle is 78

The range is 54 and the median is 78
------------------------------------------------------------------------------------------------------
Hope this helps!
6 0
3 years ago
HELPPP The number of members in the Triathlon Club was 36 in 2001 and has increased by 20% each year. Which exponential growth m
levacccp [35]

Answer:

C. y=36(1.2)t

Step-by-step explanation:

The number of members in the Club in t years after 2001 is given by an equation in the following format:

y = y(0)(1+r)^{t}

In which y(0) is the number of members in 2001 and r is the growth rate, as a decimal.

The number of members in the Triathlon Club was 36 in 2001 and has increased by 20% each year.

This means that y(0) = 36, r = 0.2

So

y = y(0)(1+r)^{t}

y = 36(1+0.2)^{t}

y = 36(1.2)^{t}

The correct answer is C.

5 0
3 years ago
Please answer 60....I don't understand
bonufazy [111]
So you basically just add up all of the numbers for the number sentence, so:
1800+2150+675+2300+665+95+250+1150+225+750+530. So the sum of those is the new balance, which is $10590
7 0
3 years ago
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