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kirza4 [7]
3 years ago
14

The net of a triangular pyramid is composed of one triangle and three rectangles. True False

Mathematics
2 answers:
ryzh [129]3 years ago
6 0

Answer:

True

Step-by-step explanation:

vlada-n [284]3 years ago
6 0

Answer:

false

Step-by-step explanation:

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A Kite of Area 255 m2 has one diagonal of length 9m . find the length of the other diagonal
Bas_tet [7]

\\ \rm\longmapsto Area=255m^2

\\ \rm\longmapsto LB=255

\\ \rm\longmapsto 9L=255

\\ \rm\longmapsto L=\dfrac{255}{9}

\\ \rm\longmapsto L=28.3m

6 0
3 years ago
What kind of sequence is the pattern 15, 17, 20, 24, 29,
VikaD [51]

\implies {\blue {\boxed {\boxed {\purple {\sf { \: 15, 17, 20, 24, 29,35, 42}}}}}}

\sf \bf {\boxed {\mathbb {Step-by-step\:explanation:}}}

\: 15, 17, 20, 24, 29,35, 42

➺ \: 15 + 2 = 17

➺\: 17 + 3 = 20

➺\: 20 + 4 = 24

➺\: 24 + 5 = 29

➺\: 29 + 6 = 35

➺\: 35 + 7 = 42

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

7 0
3 years ago
Tanner is picking three varieties of apples at an orchard: Gala, Fuji, and Jazz. Each type of apple has a different cost per pou
Makovka662 [10]

Answer:

2g + 2f = 5.16

7g + 9f = 21.24

Step-by-step explanation:

Let

Gala = g ; Fuji = f ; jazz = j

g + f + j = 5.16 - - - (1)

j = g + f - - - (2)

From (1):

g + f + g + f = 5.16

2g + 2f = 5.16 - - - (3)

Total pound picked by Tanner = 12

3 Pounds of g ; 5 pounds of f

j = 12 - (5 +3) = 4 pounds

3g + 5f + 4j = 21.24 - - - (4)

3g + 5f + 4(g + f) = 21.24

3g + 5f + 4g + 4f = 21.24

7g + 9f = 21.24 - - - - - (5)

6 0
3 years ago
Given the volume of Figure A is 512cm ^3and Figure B is 343cm^3, find the ratio of the perimeter from Figure A to Figure B.
sp2606 [1]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\[2em] \begin{array}{ccccllll} &\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\ \cline{2-4}&\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}\\\\[-0.35em] ~\dotfill

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{\textit{figure A}}{\textit{figure B}}\qquad \qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{512}}{\sqrt[3]{343}}\qquad \begin{cases} 512=&2^9\\ &2^{3\cdot 3}\\ &(2^3)^3\\ 343=&7^3 \end{cases}\implies \cfrac{s}{s}=\cfrac{\sqrt[3]{(2^3)^3}}{\sqrt[3]{7^3}} \\\\\\ \cfrac{s}{s}=\cfrac{2^3}{7}\implies \cfrac{s}{s}=\cfrac{8}{7}\implies s:s = 8:7\impliedby \textit{ratio of the }\stackrel{sides~and}{perimeters}

5 0
4 years ago
Find the value of y 74 77 89 96
Morgarella [4.7K]
The external angle (53°) is half the difference of the intercepted arcs (y°, 180°), so we have
  53 = (180 - y)/2
  106 = 180 - y
  y = 180 - 106
  y = 74

The appropriate choice for the value of y is ...
  74
4 0
4 years ago
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