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3 years ago

PLEASE HELP!! Find the area

Mathematics

1 answer:

WARRIOR [948]3 years ago

6 0

Step-by-step explanation:

Area= length × width

= 16m × 6m

= 96m

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Solve for x please show work

Serggg [28]

Answer:

I am seeing you a LOT

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP! ILL GIVE BRAINIEST!!!

jasenka [17]

The answer would be

Fraction 3/10
Percent 30%
Decimal 0.3

There is 10 parts and it ask for probability of 3 numbers which would be 3/10

8 0

2 years ago

A deep sea diver started at sea level (0 feet) and dove at a rate of 5.6 feet per minute. If the diver dove for ½ hour, what rat

Leona [35]

Given:

A deep sea diver started at sea level (0 feet).

Rate of diving = 5.6 feet per minute.

Time = $\dfrac{1}{2}$ hour

To find:

The rational number that represents his position relative to sea level.

Solution:

We know that,

1 hour = 60 minutes

$\dfrac{1}{2}$ hour = 30 minutes

A deep sea diver, dove at a rate of 5.6 feet per minute.

Distance covered in 1 minute = 5.6 feet

Distance covered in 30 minute = 30 × 5.6 feet

= 168 feet

The diver dove 168 feet in $\dfrac{1}{2}$ hour. Since it is below the sea level, therefore it should be negative.

So, the rational number that represents his position relative to sea level is $-168$ feet.

Therefore, the correct option is D.

5 0

3 years ago

so i have goodknews and bad knew my uncle got out of jail but he cant live with us anymore I'm so sad because he has been there

Marina CMI [18]

Answer:

omg i am soooo sorry :(

Step-by-step explanation:

3 0

3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

3 years ago