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Feliz [49]
3 years ago
9

PLEASE HELP!! Find the area

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0

Step-by-step explanation:

Area= length × width

= 16m × 6m

= 96m

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Solve for x please show work
Serggg [28]

Answer:

I am seeing you a LOT

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP! ILL GIVE BRAINIEST!!!
jasenka [17]
The answer would be

Fraction 3/10
Percent 30%
Decimal 0.3

There is 10 parts and it ask for probability of 3 numbers which would be 3/10
8 0
2 years ago
A deep sea diver started at sea level (0 feet) and dove at a rate of 5.6 feet per minute. If the diver dove for ½ hour, what rat
Leona [35]

Given:

A deep sea diver started at sea level (0 feet).

Rate of diving = 5.6 feet per minute.

Time = \dfrac{1}{2} hour

To find:

The rational number that represents his position relative to sea level.

Solution:

We know that,

1 hour = 60 minutes

\dfrac{1}{2} hour = 30 minutes

A deep sea diver, dove at a rate of 5.6 feet per minute.

Distance covered in 1 minute = 5.6 feet

Distance covered in 30 minute = 30 × 5.6 feet

                                                    = 168 feet

The diver dove 168 feet in \dfrac{1}{2} hour. Since it is below the sea level, therefore it should be negative.

So, the rational number that represents his position relative to sea level is -168 feet.

Therefore, the correct option is D.

5 0
3 years ago
so i have goodknews and bad knew my uncle got out of jail but he cant live with us anymore I'm so sad because he has been there
Marina CMI [18]

Answer:

omg i am soooo sorry :(

Step-by-step explanation:

3 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
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