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3 years ago

Question 2 (1 point)

Mathematics

2 answers:

anzhelika [568]3 years ago

6 0

Answer:

on the bottom equation you can subtract 1 from both sides, x = 2y+1 so you substitute that in for x on the other equation, 7(2y+1) - 2y = 1 or 14y + 7 -2y = 1 then 12y = -6 y = -1/2 which you put back into the other equation, 2(-1/2) = x -1 so -1 = x - 1 then x = 0, the answer is (0, -1/2)

kompoz [17]3 years ago

3 0

On the bottom equation divide all numbers and variables by 2 to get the equation y=2x-2 then write the equation 7x-2(2x-2)=1 distribute to get 7x-4x+4=1 then combine like terms to get 3x+4=1 subtract 4 by one to get 3x=-3 then divide both sides by 3 to get x=-1
next plug in x to your y= equation to get the equation 2(-1)-2=y then solve by multiplying 2by -1 to get -2-2=y then solve and get y=4 so your points are (-1,4)

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ddd [48]

• Move x to the other side

7y=21-3x

• Divide by 7

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Consider a function f(x) such that f(5x) =x-5/5x-1. Find f(x) and hence write down the domain of f(x).

nasty-shy [4]

Answer:

$f(x) = \frac{x - 25}{5x - 5}$

Domain: $x \ne 1$

Step-by-step explanation:

Given

$f(5x) = \frac{x - 5}{5x - 1}$

Required

Determine f(x) and its domain

To determine f(x), we replace 5x with x in f(5x)

So, we have:

$f(5x) = \frac{\frac{5x}{5} - 5}{5x - 1}$

$f(x) = \frac{\frac{x}{5} - 5}{x - 1}$

Take LCM

$f(x) = \frac{\frac{x - 25}{5}}{x - 1}$

$f(x) = \frac{x - 25}{5} * \frac{1}{x-1}$

$f(x) = \frac{x - 25}{5x - 5}$

To get the domain, we set the denominator as

$5x - 5 \ne 0$

$5x \ne 5$

$x \ne 1$

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Answer:

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Step-by-step explanation:

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Read 2 more answers

The area of a rectangle is 14 m2 , and the length of the rectangle is 3 m less than double the width. find the dimensions of the

muminat

Width =3.5, length = 4

Let's make a few equations to summarize what we know.:
a = 14
l = 2w -3
a = wl

Now let's substitute the expression for l into the expression for area and solve.
a = w(2w - 3)
a = 2w^2 - 3w
14 = 2w^2 - 3w

0 = 2w^2 - 3w - 14

which factors into
(2w - 7) (w + 2)

Solving for w
2w - 7 = 0
2w = 7
w = 3.5

w+2 = 0
w = -2

So w can be either 3.5 or -2. Since a negative width doesn't make sense, w = 3.5

Let's verify
w = 3.5
l = 2w - 3
l = 2*3.5 - 3
l = 7 - 3
l = 4
a = wl
a = 3.5 * 4
a = 14

So the width is 3.5 and the length is 4.

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Answer:

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