A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
Learn more about translation rule:
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Answer:
4.4 ft/s
Step-by-step explanation:
Height = 15ft
Rate= 5 ft/s
Distance from the man to the kite= 32ft
dh/dt = 5 ft/s
h = √32^2 - 15^2
h = √ 1025 - 225
h = √800
h = 28.28ft
D = √15^2 + h^2
dD/dt = 1/2(15^2 + h^2)^-1/2 (2h) dh/dt
= h(225 + h^2)^-1/2 dh/dt
= (h / √225 + h^2)5
= (28.28 / √225 + 28.28^2)5
= (28.28 / √1024.7584)5
= (28.28/32)5
= 0.88*5
= 4.4 ft/s
Nicki:x (12)
Claudia:x+5
Hunter:12
Decade=10 years
Dog: x-10
Philip:(x-10)+3=x-7
Sara: x-8
Sara:4
Answer:
no
Step-by-step explanation:
