<span>11,550 km has to be changed to 11,550,000 meters
G · m · t² = 4 · π² · r³ we can change that to
</span>t² = (4 · π² · r³) / <span>(G · m )
t^2 = 4*PI^2*r^3 / (G*m)
</span>t^2 = 4*PI^2*<span>(11,550,000)^3 / 6.67*10^-11*5.98*10^24kg
t^2 = </span>
<span>
<span>
<span>
6.083*10^22
</span>
</span>
</span>
<span><span>
</span>
</span>
/
<span>
<span>
<span>
3.9</span></span></span>9 * 10^14
t^2 =
<span>
<span>
<span>
152,500,000</span></span></span>
t = <span>12,350 seconds
</span>and its orbital distance it travels is 11,550 * 2*PI = 70,050 kilometers
Therefore, it is traveling at 70,050 km / 12,350 second which equals
5.67 km per second which <em>is 5,670 meters per second.</em>
Source:
http://www.1728.org/kepler3a.htm
3 years
ar(n)=total a is the first number which is 7000 r is the common ratio which is 100%+2%=102 102 divided by 100 giving u 1.02(interest) so ar(n)=sum n is written as power.....and is the number of years so 7000*1.02(n)=(7000+420) 1.02(n)=7420/7000 1.02(n)=1.06 log10 1.02(n)=log10(1.06) ( multiply log10 with both) n=log10(1.06)/log10 (1.02) u get 2.94 which is round off to 3 so 3 years.. hope This helps :)
The answer would be B) 6x + 2.
5x + 2 + x (simplify)
(5x + x) + 2 (gather like terms)
6x + 2 (simplify).
Answer:
12.5r
Step-by-step explanation:
You just add all the numbers together and then add the r at the end it’s pretty easy when you know that
