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2 years ago

Write the equation of a line with a slope of -7/2 passing through the point 2,-4

Mathematics

1 answer:

fiasKO [112]2 years ago

5 0

Answer:

y = -7/2x+3

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = -7/2 x+b

Substitute the point into the equation

-4 = -7/2(2) +b

-4 = -7+b

Solving for b

-4+7 = -7+b+7

3 = b

The equation is y = -7/2x+3

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3 years ago

Read 2 more answers

34.98+12.24=?<br>answers please

Ksivusya [100]

Answer:

Hello!

After reading your question I have calculated the correct answer to be:

47.22

Step-by-step explanation:

The way I solved this equation was I first split the equation into two parts.

I took the two whole numbers, being "34" and "12", and made their own equation:

"34+12=?"

And then I took the two partial numbers "0.98" and "0.24" and made their own equation:

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I then solved both equations:

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And added those two solutions together to come up with the final solution:

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Hope this helped!

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2 years ago

A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte

AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

$\angle SPR$ =Angle subtended by the statue to where you are standing.

$\angle x=\angle RPQ$ = which is unknown.

Let us begin solving now. The first step is to find the angle $\angle x$ which can be found by using the following trigonometric ratio in $\Delta PQR$ :

$tan(x)=\frac{RQ}{PQ} =\frac{21}{57}$

Which gives $\angle x$ to be:

$\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}$

Now, we know that $\angle x$ and $\angle SPR$ can be added to give us the complete angle $\angle SPQ$ in the right triangle $\Delta SPQ$ .

We can again use the tan trigonometric ratio in $\Delta SPQ$ to solve for the height of the statue, h.

This can be done as:

$tan(\angle SPQ)=\frac{SQ}{PQ}$

$tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}$

$tan(27.32^0)=\frac{h+21}{57}$

$\therefore h+21=57tan(27.32^0)$

$h\approx8.45 ft$

Thus, the height of the statue is approximately, 8.45 feet.

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3 years ago

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enyata [817]

Answer:

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Step-by-step explanation:

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