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2 years ago

What is the name of an angle that is formed by one side of a triangle and the extension of an adjacent side?

Mathematics

2 answers:

svet-max [94.6K]2 years ago

5 0

Answer:

An exterior angle is formed by one side of a triangle and the extension of another side. Remote interior angles are the interior angles of a triangle that are not adjacent to a given angle.

Svetach [21]2 years ago

5 0

Answer:

exterior angle

Step-by-step explanation:

Because it is formed by one side of a triangle. Also, if you add the adjacent interior angles, you would get the value of the exterior angle.

Hope this helped!

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The perimeter of the warehouse can be modeled by which of the following? P = 4(348 feet) P = (348 feet)2 P = 2(348 feet) + 2(348

Nikitich [7]

P= 4(348) because assuming the wear house has four sides that is the only logical answer

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3 years ago

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Delicious77 [7]

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2 years ago

Ahhhh help everyone help me solve this ....

vovangra [49]

Answer:

$y = \frac{18 {w}^{2} {x}^{2} {z}^{2} }{25}$

Step-by-step explanation:

$\frac{3wx}{ \sqrt{2y} } = \frac{5}{2z} \\ \\ \sqrt{2y} \times 5 = 3wx \times 2z \\ \\ \sqrt{2y} \times 5 = 6wxz \\ \\ \sqrt{2y} = \frac{6wxz}{5} \\ \\ {( \sqrt{2y} })^{2} = {( \frac{6wxz}{5} })^{2} \\ \\ 2y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \div 2 \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \times \frac{1}{2} \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{50} \\ \\ \\ y = \frac{18 {w}^{2} {x}^{2} {z}^{2} }{25}$

I hope I helped you^_^

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2 years ago

Janet has $120. If she saves$20 per week, in how many days will she have $500?

maxonik [38]

She will have $500 in 5 days because when she takes out the 20 every week she will have had $100 so to make $500 she will have to have made 5 $100

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3 years ago

I’m Really lost if I could get a answer it would be greatly appreciated

Nataly [62]

<h3>Answers:</h3>

$f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}$

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Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out $\left(\sqrt{x-1}+5\right)^2$

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3 years ago