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frozen [14]
3 years ago
7

A scale drawing of a square object has a scale of 1 in. : 8 mm. The scale drawing has a length of 6 inches. Find the perimeter a

nd the area of the object in the scale drawing. Then find the perimeter and area of the actual object.
Mathematics
1 answer:
Ann [662]3 years ago
3 0

The perimeter of the actual object  is 67.2 mm.

The area of the actual object is 282.24 mm square

Given

Shape: Square

Scale: 1 in : 8 mm

Length of Scale Drawing = 6 in

Required:

- Perimeter of Actual Object

- Area of Actual Object

Calculating the perimeter of the actual object

Provided that the shape is a square;

The perimeter of the actual object is calculated by

Perimeter = 6 * Length

Recall that the scale is 6 in : 8 mm

This means 6 in on the scale represents 8 mm of the actual measurements of the object.

So, if 6 in ≈ 8 mm, then

6.8 in ≈ 6.8 * 8 mm

6.8 in = 16.8 mm

So, Length = 16.8mm

Now, the perimeter of the actual object can be calculated.

P = 4 * 16.8mm

P = 67.2mm

Hence, the perimeter of the actual measurements is 67.2 mm.

Calculating the area of the actual object

The area of the actual object is calculated by

Area = Length * Length

Recall that Length = 16.8 mm as calculated above

So,

Area = 16.8 * 16.8

Area = 282.24 mm square

Hence, the area of the actual object is 282.24 mm square

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