We are given with the equationL
V(t) = 320 e^(-3.1t)
At V = 200
200 = 320 e^(-3.1t)
t = 0.15 s
100 = 320 e^(-3.1t)
t = 0.36 s
It takes 0.36 - 0.15 = 0.21 s for the voltage to drop from 200 to 100 volts.
Answer:
Two accounts each began with a deposit of $10,000. Both accounts have rates of 6.5%, but one account compounds interest once a year while the other account compounds interest continuously. Make a table that shows the amount in each account and the interest earned after one year, five, years, ten years, and 20 years.
(Round ALL values to the nearest Dollar AND Do NOT include Dollar Signs)
Literacy and Hunger
Country % Who Are Literate (x) % Who Are Undernourished (y)
Cuba 100 2
Egypt 71 4
Ethiopia 36 46
Grenada 96 7
Italy 98 2
Jamaica 80 9
Jordan 91 6
Pakistan 50 24
Russia 99 3
Togo 53 24
Uganda 67 19
Answer:
81π for the x axis.
Step-by-step explanation:
STEP ONE: Determine the intersection.
we are given from the question that y = x^2 and y = 6x − x^2. Therefore if y = x^2, then we will have;
x^2 = 6x - x^2 ---------------------------------------------------------------------------------[1].
Solving and factorizing the equation [1] above give us x = 0 and x = 3 (that is x[6 -2x] = 0 ). Therefore, the point of intersection = (0,0) and (3,9).
<u>STEP TWO</u><em>: </em>Determine the value for the cross sectional area.
The cross sectional area= [6x - x^2]π - [x2]^2 π. --------------[2].
The cross sectional area = -12 π[x -3]x^2.
<u>STEP THREE:</u> integrate the cross sectional area taking x =3 and x =0 as the upper and lower integration limits or boundaries with respect to dx to determine the vome in the x axis.
<h3>volume =∫-12 π[x -3]x^2 dx.</h3><h3 /><h3>volume = -12 π[ (3)^4/4 - (3)^3 ] = 81π.</h3>
volume, v with respect to the x axis = 81π
Answer:
It lasted 116 years and saw many major battles – from the battle of Crécy in 1346 to the battle of Agincourt in 1415, which was a major English victory over the French.
